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seropon [69]
3 years ago
10

Which scientist was the first to accurately measure the speed of light?

Physics
2 answers:
oksano4ka [1.4K]3 years ago
6 0

Answer:

Olaus Roemer was the first scientist to accurately measure the speed of  light.

Explanation:

nekit [7.7K]3 years ago
5 0
D. Olaus Roemer was the 1st
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Which of the following can be studied by science?
Alla [95]
D. Natural phenomena
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3 years ago
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Kay [80]
It’s would be C.

mark me brain
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3 years ago
A horizontal circular wire loop of radius 0.7 m lies in a plane perpendicular to a uniform magnetic field that is pointing down
Maru [420]

Answer:

\epsilon=1.10\ V

Explanation:

It is given that,

Radius of the circular loop, r = 0.7 m

Magnetic field, B = 0.44 T

In 0.14 s the wire is reshaped from a circle into a square, but remains in the same plane.

Area of the circular wire,

A_1=\pi r^2

A_1=\pi (0.7)^2=1.539\ m^2

For the area of square,

The circumference of wire, C=2\pi r=2\pi \times 0.7=4.39\ m

Side of square, l=\dfrac{4.39}{4}=1.09\ m

Area of square, A_2=1.09^2=1.188\ m^2

An emf is induced in the loop due to change in its area. The induced emf is given by :

\epsilon=-B\dfrac{dA}{dt}

\epsilon=-B\dfrac{A_2-A_1}{t}

\epsilon=-0.44\times \dfrac{1.188-1.539}{0.14}  

\epsilon=1.10\ V

So, the magnitude of the average induced emf is 1.10 volts. Hence, this is the required solution.

3 0
3 years ago
A car travels 35 km west and 90 km north in two hours what is its average velocity?
blagie [28]
Average velocity =  Total Displacement / Total time taken

Total displacement is the distance from starting to end point.

35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle. 

So displacement = \sqrt{35^2+90^2}

= 96.56 km

So, Total displacement = 96.56 km

So, Average Velocity = 96.56 / 2  = 48.28 km/hr
8 0
3 years ago
The half-life of a certain element is 100 days. How many half-lives will it be before only one-eighth of this element remains?
Natalka [10]

Answer:

3

Explanation:

The half-life is the time it takes for the amount of radioactive isotope to halve. Therefore, we have:

- After 1 half-life, only 1/2 of the element will be left

- After 2 half-lives, only 1/4 of the element will be left

- After 3 half-lives, only 1/8 of the element will be left

So, it will take 3 half-lives for the element to become 1/8 of its original amount.

Mathematically, this can be also verified by using the equation

\frac{N(t)}{N_0}=(\frac{1}{2})^\frac{t}{\tau_{1/2}}

where

N(t) is the amount of the element left at time t

N0 is the initial amount of the element

\tau_{1/2} is the half-life

Substituting t=3\tau_{1/2} (3 half-lives), we find

\frac{N(t)}{N_0}=(\frac{1}{2})^3=\frac{1}{8}

7 0
3 years ago
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