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Reptile [31]
3 years ago
8

Let this be an easy 5 points to your brainly points all I ask is for you to answer with "thank you"

Chemistry
1 answer:
Sergio039 [100]3 years ago
4 0

Answer:

1. Double displacement reaction

2. Trisodium phosphate and potassium hydroxide

3. Sodium hydroxide and Potassium phosphate

Explanation:

1)

The given chemical reaction is as follows.

Na_{3}PO_{4}+KOH\rightarrow NaOH+K_{3}PO_{4}

The balanced chemical reaction is as follows.

Na_{3}PO_{4}+3KOH\rightarrow 3NaOH+K_{3}PO_{4}

In the above reaction two reactants are exchange their cations. Therefore, it is a double displacement reaction.

2)

Na_{3}PO_{4}+3KOH\rightarrow 3NaOH+K_{3}PO_{4}

In the above reaction left side of the reaction is considered as reactants.

Na_{3}PO_{4} - Trisodium phosphate

KOH - Potassium hydroxide

3)

Na_{3}PO_{4}+3KOH\rightarrow 3NaOH+K_{3}PO_{4}

In the above reaction right side of the reaction is considered as products.

NaOH - Sodium hydroxide

K_{3}PO_{4} - Potassium phosphate.

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Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. Determine the molar sol
Kaylis [27]

Hey there!:

Given the reaction:

 NaBr  ⇌  Na⁺ +  Br⁻

  ↓              ↓         ↓

0.150M      0.150M     0.150M


AgBr ⇌ Ag⁺   + Br⁻

 ↓            ↓          ↓

 x            x         0.150M


Therefore:

Ksp = x * 0.150

x = ( 7.7 * 10⁻¹³ ) / 0.150

x = 5.1 * 10⁻¹²


Answer B


Hope that helps!

5 0
3 years ago
1. If temperature is increased, the number of<br> collisions per second
andrey2020 [161]

Answer:

Increases

Explanation:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions.

4 0
3 years ago
Class science A lunar eclipse occurs when
NeTakaya

Answer:

when the moon passes through earth's shadow

Explanation:

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Determine the concentrations of BaBr2, Ba2 , and Br– in a solution prepared by dissolving 1.18 × 10–4 g BaBr2 in 1.00 L of water
Anika [276]
Supposing complete ionization: 
<span>BaBr2 → Ba{2+} + 2 Br{-} </span>

<span>(2.23 × 10^–4 g BaBr2) / (297.135 g BaBr2/mol) / (2.00 L) = 3.75 × 10^-7 mol/L BaBr2 </span>

<span>(3.75 × 10^-7 mol/L BaBr2) x (1 mol Ba{2+} / 1 mol BaBr2) = 3.75 × 10^-7 mol/L Ba{2+} </span>

<span>(3.75 × 10^-7 mol/L BaBr2) x (2 mol Br(-} / 1 mol BaBr2) = 7.50 × 10^-7 mol/L Br{-}</span>
5 0
3 years ago
: If you know that a ∝ b and a ∝ c, then you can also say that a ∝ bc, or the product of b and c. Take the above three proportio
aleksley [76]

Answer:

V ∝ abc

Explanation:

This task is a joint variation task involving only direct proportionality:

Direct variation is one in which two variables are in direct proportionality to each other. This means that as one increases, the other variable also increases and vice - versa.

Joint variation is one in which one variable is dependent on two or more variables and varies directly as each of them.

In this exercise:

If a ∝ b and a ∝ c, then a ∝ bc

Taking the above three proportionalities,

V ∝ a ∝ b ∝ c

V ∝ a ∝ bc

V ∝ abc

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3 years ago
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