The approximate molar mass of lauryl alcohol is 183 g/mol.
As per Raoult's law:

Tb = the freezing point of benzene (5.5oC), Ts = the freezing point of the solution, K = the cryoscopic constant (5.12 K*kg/mol for benzene), and Cm = the molality of the solution.
/M
=
where ml is the mass of lauryl alcohol and ms is the mass of the solvent.
=K
/M
Therefore, M=
=
=183 g/mol.
<h3>Lauryl alcohol </h3>
An organic substance called lauryl alcohol is created industrially from coconut or palm kernel oil. It is an alcoholic fat. The use of sodium lauryl sulfate and other sulfate esters of lauryl alcohol as surfactants is extremely common. In shampoos, sodium laureth sulfate, ammonium laureth sulfate, and sodium lauryl sulfate are all utilized. Lauryl alcohol has a floral scent and is flavorless and colorless. In addition to being a flavor-enhancing food additive, lauryl alcohol is also used to create medicines, lubricating lubricants, surfactants, and monolithic polymers. Lauryl alcohol is a kind of emollient used in cosmetics. Lauryl alcohol, a significant scent, and 1-bromododecane, an alkylating agent used to increase the lipophilicity of organic molecules, are both precursors to Lauryl alcohol.
A solution of 5. 00 g of lauryl alcohol in 0. 100 kg of benzene freezes at 4. 1°c. what is the approximate molar mass of lauryl alcohol?
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GROUNDWATER is the term used for water that soak into the ground, fills the openings in the soil and trickles into cracks and spaces in rock layers.
Groundwater is usually found underneath the earth surface in the spaces and cracks in sand, rock and soil. It is stored in aquifers. Ground water usually connect with various water bodies such as oceans, rivers and streams and it is always a natural source of water for vegetation. Ground water is a very important natural resource.
Answer:
260 kPa
Explanation:
To answer this problem we can use <em>Gay-Lussac's law</em>, which states that at a constant volume (such as is the case with a rigid container):
Where in this case:
- T₂ = 273 °C ⇒ 273 + 273.16 = 546 K
We <u>input the data</u>:
- 340 kPa * 546 K = P₂ * 713 K
And <u>solve for P₂</u>:
Explanation:
but.......you havent attached a picture?