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Rina8888 [55]
3 years ago
9

WHY ACETIC ACID IS STRONGER IN STRENGHT THAN CHLOROACETIC ACID ...?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
6 0
For this question, I think it is the other way around. It is true that chloroacetic acid is stronger in strength than acetic acid. Acid strength is measured as the equilibrium constant of the reaction <span>HA -----> H+ + A- 

</span><span> In acetic acid, the anion produced by dissociation is CH3-COO-; in chloroacetic acid it is CH2Cl-COO-. Comparing the two, in the first one the negative charge is taken up mostly by the two oxygen atoms. In the second there is also an electronegative chlorine atom nearby to draw more charge towards itself. Therefore, the charge is less concentrated in the chloroacetate ion than it is in the acetate ion, and, accordingly, chloroacetic acid is stronger than acetic acid. </span>
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Hemoglobin is the protein that transports oxygen in mammals. Different species of mammals have slightly different forms of hemog
Anna35 [415]

Answer;

= 64561.95 g/mole

Explanation;

mass of Fe in 100g = .346g

= .346 / 55.8452 moles

= 0.0061957 moles  

These represent 4 moles of Fe in the molecule so moles of hemaglobin

=  0.0061957/4  

= 0.0015489 moles  

these are in 100 g so mass of 1 mole = 100 / 0.0015489

= 64561.95 g / mole

molar mass of hemoglobin = 64561.95 g/mole

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3 years ago
Where are elements with similar chemical properties found on the periodic table?
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All the members of a family of elements have the same number of valence electrons and similar chemical properties. The horizontal rows on the periodic table are called periods.
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Name two control substance?
guapka [62]
The two control bases would be water and salt.
6 0
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Whats the chemical equation for concentrated hydrochloric acid<br> and dilute sulfuric acid
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3 0
3 years ago
A metal crystallizes in a body-centered cubic unit cell. The radius of one atom = 2.30 x 10 -8 cm. The density of the metal is 0
maw [93]

Answer:

25.41 g/mol is molar mass of metal.

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of metal = 0.867 g/cm^3

Edge length of cubic unit cell= a = ?

Radius  of the atom of metal = r = 2.30\times 10^{-8} cm

a=2\times r=2\times 2.30\times 10^{-8} cm=4.60\times 10^{-8} cm

Atomic mass of metal =M

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

0.867 g/cm^3=\frac{2\times M}{6.022\times 10^{23} mol^{-1}\times (4.60\times 10^{-8} cm)^{3}}

M = 25.41 g/mol

25.41 g/mol is molar mass of metal.

6 0
3 years ago
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