D because these are the biggest particles, and are therefore, the most dense.
Answer:
4.13×10²⁷ molecules of N₂ are in the room
Explanation:
ideal gases Law → P . V = n . R . T
Pressure . volume = moles . Ideal Gases Constant . T° K
T°K = T°C + 273 → 20°C + 273 = 293K
Let's determine the volume of the room:
18 ft . 18 ft . 18ft = 5832 ft³
We convert the ft³ to L → 5832 ft³ . 28.3L / 1 ft³ = 165045.6 L
1 atm . 165045.6 L = n . 0.082 L.atm/mol.K . 293K
(1 atm . 165045.6 L) / 0.082 L.atm/mol.K . 293K = n
6869.4 moles of N₂ are in the room
If we want to find out the number of molecules we multiply the moles by NA
6869.4 mol . 6.02×10²³ = 4.13×10²⁷ molecules
Answer:
Mass = 15.1 g
Explanation:
Given data:
Number of moles of NaBH₄ = 0.40 mol
Mass in gram = ?
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of NaBH₄ = 37.83 g/mol
By putting values,
Mass = 0.40 mol × 37.83 g/mol
Mass = 15.1 g
