Suppose a car travels 106 km at a speed of 28 m/s and uses 1.9 gals of gasoline in the process. Only 30% of the gasoline goes in
1 answer:
Answer:
a) The magnitude of the force is 968 N
b) For a constant speed of 30 m/s, the magnitude of the force is 1,037 N
Explanation:
<em>NOTE: The question b) will be changed in other to give a meaningful answer, because it is the same speed as the original (the gallons would be 1.9, as in the original).</em>
Information given:
d = 106 km = 106,000 m
v1 = 28 m/s
G = 1.9 gal
η = 0.3
Eff = 1.2 x 10^8 J/gal
a) We can express the energy used as the work done. This work has the following expression:
Then, we can derive the magnitude of the force as:
b) We will calculate the force for a speed of 30 m/s.
If the force is proportional to the speed, we have:
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Answer:
Option D: Four times the original speed.
Explanation:
A centripetal force accelerates a body by changing the direction of the body's velocity without changing the body's speed.
The speed(v) is therefore constant, thereby making the magnitudes of the of the acceleration and the force constant.
The formula used to calculate the Centripetal force is given below:
where F represents the Centripetal force, m represents the mass of the moving body, v represents the speed or velocity at which the body is moving and r represents the radius.
Making the speed the subject of the formula:
Therefore, when the radius (r) is changed to 4r, i.e r = 4r
speed(v) becomes
After comparing, the difference between the speeds is Four times the original speed.
A) The car overtakes the truck after 7.56 s
B) Initial distance between car and truck: 37.1 m
C) Speed of the truck: 15.9 m/s, speed of the car: 25.7 m/s
D) See graph in attachment
Explanation:
A)
The truck starts from rest and has a constant acceleration, so its position at time t can be written as
where
d is the initial distance between the truck and the car (the truck starts some distance ahead of the car)
is the acceleration of the truck
The car position instead it is given by the equation
where
is the acceleration of the car
The car overtakes the truck when the truck has moved 60.0 m, so when
Therefore, solving the equation, we find the time t when this occurs:
B)
In order to find the initial distance between the car and the truck (d), we have to calculate first the distance covered by the car during these 7.56 s. It is given by:
This means that after 7.56 s, when the car reaches the truck, the car has covered 97.2 m while the truck has covered 60 m. However, their positions are now equal, so we can write:
And by solving the equation, we find the value of d, the initial distance between car and truck:
C)
In order to find the speed of each vehicle, we use the following suvat equation:
where
u is the initial velocity
a is the acceleration
t is the time
For the truck, we have:
u = 0
So its speed after t = 7.56 s is
For the car, we have
u = 0
So its speed after t = 7.56 s is
D)
Find the graph required in attachment.
On the x-axis, it is represented the time in seconds. On the y-axis, it is represented the position in meters.
Both curves are in the shape of a parabola since the motion of both vehicles is an accelerated motion.
The curve that starts at -37.1 m is the curve representing the car: in fact, the car starts behind the truck by 37.1 m. The curve that starts from x = 0, t= 0 is that of the truck.
The two curves meets when t = 7.56 s: at that time, the two vehicles have reached the same position, and we see that occurs when x = 60 m, which means that this happens when the truck has covered 60 meters.
Learn more about accelerated motion:
#LearnwithBrainly
Assume theres no air reaistance. (or else the ball will oppose the motion of the ball, hence decrease the velocity increase)
see if there are any problems!
see if there are any problems!