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malfutka [58]
3 years ago
15

A student uses the right-hand rule as shown. an illustration with a right hand with fingers curled and thumb pointed up. what is

the direction of the magnetic field in front of the wire closest to the student? up right down left
Physics
1 answer:
Afina-wow [57]3 years ago
6 0

The direction of the magnetic field in front of the wire closest to the student is on the left. The direction is found by the right-hand rule.

<h3>What is the right-hand rule?</h3>

The right-hand rule is a popular mnemonic for remembering how axes in three-dimensional space are oriented.

The fact that the three axes of three-dimensional space have two different orientations gives birth to the majority of the many left-hand and right-hand rules.

Using the right-hand rule, we can recall this diagram. Your thumb points in the direction of the magnetic force pushing on the moving charge

If you point your pointer finger in the direction of the positive charge and then your middle finger in the direction of the magnetic field.

To learn more about the right-hand rule refer to the link;

brainly.com/question/9750730

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A doorframe is twice as tall as it is wide. There is a positive charge on the top left corner and an equal but negative charge i
Andrei [34K]

Answer:

α = 141.5°  (counterclockwise)

Explanation:

If

q₁ = +q

q₂ = -q

q₃ < 0

b = 2*a

We apply Coulomb's Law as follows

F₁₃ = K*q₁*q₃ / d₁₃² = + K*q*q₃ / (2*a)² = + K*q*q₃ / (4*a²)

F₂₃ = K*q₂*q₃ / d₂₃² = - K*q*q₃ / (5*a²)

(d₂₃² = a² + (2a)² = 5*a²)

Then

∅ = tan⁻¹(2a/a) = tan⁻¹(2) = 63.435°

we apply

F₃x = - F₂₃*Cos ∅ = - (K*q*q₃ / (5*a²))* Cos 63.435°

⇒  F₃x = - 0.0894*K*q*q₃ / a²

F₃y = - F₂₃*Sin ∅ + F₁₃

⇒  F₃y = - (K*q*q₃ / (5*a²))* Sin 63.435° + (K*q*q₃ / (4*a²))

⇒  F₃y = 0.0711*K*q*q₃ / a²

Now, we use the formula

α = tan⁻¹(F₃y / F₃x)

⇒  α = tan⁻¹((0.0711*K*q*q₃ / a²) / (- 0.0894*K*q*q₃ / a²)) = - 38.5°

The real angle is

α = 180° - 38.5° = 141.5°  (counterclockwise)

4 0
4 years ago
2. Which of the following is an example of acceleration.
N76 [4]
C
<span>Write at least 20 characters to explain it well.</span>
3 0
3 years ago
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Why are some electromagnetic waves harmful to you but others are not?
MariettaO [177]
The Right Answer Is: <span>the high frequencies and shorter wavelengths penetrates body easily.</span>
8 0
3 years ago
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A mass moves back and forth in simple harmonic motion with amplitude A and period T.
Sever21 [200]

a. 0.5 T

- The amplitude A of a simple harmonic motion is the maximum displacement of the system with respect to the equilibrium position

- The period T is the time the system takes to complete one oscillation

During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.

So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

1 T : 4 A = t : 2 A

and solving for t we find

t=\frac{(1T)(2 A)}{4A}=0.5 T

b. 1.25T

Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that

- the mass takes a time of 1 T to cover a distance of 4A

we can set the following proportion:

1 T : 4 A = t : 5 A

And by solving for t, we find

t=\frac{(1T)(5 A)}{4A}=\frac{5}{4} T=1.25 T

6 0
3 years ago
Water flows over a fall that is 125.0 m high. If the potential energy of the water is all converted to thermal energy, calculate
Pavel [41]

Answer:

ΔT = 0.29°C

Explanation:

Using the law of conservation of energy:

Potential\ Energy = Thermal\ Energy\\mgh = mC\Delta T\\gh = C\ \Delta T\\\\\Delta T = \frac{gh}{C}

where,

ΔT = Temperature difference between the water at the top and the bottom of the fall = ?

g = acceleration due to gravity = 9.81 m/s²

h = height of fall = 125 m

C = specific heat capacity of water = 4200 J/kg

Therefore,

\Delta T = \frac{(9.81\ m/s^2)(125\ m)}{4200\ J/kg^oC}\\\\

<u>ΔT = 0.29°C</u>

8 0
3 years ago
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