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malfutka [58]
2 years ago
15

A student uses the right-hand rule as shown. an illustration with a right hand with fingers curled and thumb pointed up. what is

the direction of the magnetic field in front of the wire closest to the student? up right down left
Physics
1 answer:
Afina-wow [57]2 years ago
6 0

The direction of the magnetic field in front of the wire closest to the student is on the left. The direction is found by the right-hand rule.

<h3>What is the right-hand rule?</h3>

The right-hand rule is a popular mnemonic for remembering how axes in three-dimensional space are oriented.

The fact that the three axes of three-dimensional space have two different orientations gives birth to the majority of the many left-hand and right-hand rules.

Using the right-hand rule, we can recall this diagram. Your thumb points in the direction of the magnetic force pushing on the moving charge

If you point your pointer finger in the direction of the positive charge and then your middle finger in the direction of the magnetic field.

To learn more about the right-hand rule refer to the link;

brainly.com/question/9750730

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Answer:

A) T.

Explanation:

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6 0
3 years ago
Read 2 more answers
A spring with spring constant 11.5 N/m hangs from the ceiling. A 490 g ball is attached to the spring and allowed to come to res
Natalija [7]

Answer:

The time constant is \tau = 17.5 \ s    

Explanation:

From the question we are told that

   The spring constant is  k = 11.5 \  N/m

   The mass  of the ball is  m_b  = 490 \ g  = 0.49 \ kg

   The amplitude of the  oscillation t the beginning is x =  6.70 cm = 0.067 \  m

    The amplitude after time t is  x_t = 2.20 cm = 0.022 \  m

    The number of oscillation is N  = 30

Generally the time taken to attain the second amplitude is mathematically represented as

       t  = N  *  T                                            Here  T is the period of oscillation

         t = N * 2\pi \sqrt{\frac{m}{k} }

=>     t = 30 * 2 * 3.142 *  \sqrt{\frac{ 0.490}{11.5} }

=>     t = 38.88 \  s

Generally the amplitude at time t is mathematically represented as

         x(t) = x e^{-\frac{at}{2m} }

Here a is the damping  constant so

 at  t = 38.88 \  s ,  x_t = 2.20 cm = 0.022 \  m

So  

     0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }

=>  0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }

taking natural log of both sides

=>  ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }    

=>   a = 0.028

Generally the time constant is mathematically represented as

    \tau = \frac{m}{a}      

=> \tau = \frac{0.490}{  0.028}    

=> \tau = 17.5 \ s    

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3 years ago
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34kurt

Answer:

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