Answer:
1. 16 protons, 18 electrons, 16 neutrons
2. Ba (2+) + 2 NO3 (-) + 2 Na (+) + SO4 (-) = 2 Na (+) + 2 NO3 (-) + BASO4
Explanation:
1. By looking at the number in the top left corner, we know the mass is 32. And by looking at the number in the bottom left, we know that we have 16 protons. Now the way to find neutrons is to subtract the number of protons from the mass (32-16) which will give us 16 neutrons. Now the electrons are a bit tricky. Usually, atoms have the same number of protons and electrons, hence why atoms don't usually have a charge. However, in this case we have a charge of 2- (as seen in the top right corner) so we need to add two to the number of protons to find our number of electrons (electrons are negatively charged, so if there are more of them the atom will have an overall negative charge) and when we do that we get 18. So the final answer is 16 protons, 18 electrons, and 16 neutrons.
2. This one I'm not 100% sure on since the pictures are kinda wonky but essentially the way net ionic equations are written is that whatever is aqueous/soluble (aq) will be written separate from whatever it was bonded to with the charge shown, but solids (s), liquids (l), and gases (g) are written still bonded without the charge being shown. So in this case, everything in the reaction is aqueous except for the BaSO4 product. The parentheses are used to show charges, but won't be written in an actual equation, and the equal sign is the same as the arrow. So you're equation is written as Ba (+) + 2 NO3 (-) + 2 Na (+) + So4 (2-) = 2 Na (+) + NO3 (-) + BaSO4.
Hope this helps! :)
Answer:
Li atoms readily give up one electron to form positively charged, Li+ ions. These ions have the same stable electron configuration as the noble gas helium. All Group 1 atoms can lose one electron to form positively charged ions.
Explanation:
The answer is the gaz inside the bag would expand. (A)
Answer:
0.30 M
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t = ?
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration = 1.36 M
k is the rate constant = 0.208 s⁻¹
t = 7.30 seconds
So,
![[A_t]=1.36\times e^{-0.208\times 7.30}\ M=0.30\ M](https://tex.z-dn.net/?f=%5BA_t%5D%3D1.36%5Ctimes%20e%5E%7B-0.208%5Ctimes%207.30%7D%5C%20M%3D0.30%5C%20M)
It’s B. Substitution hope this helps
