Answer:
C5H12 + 8O2 —> 5CO2 + 6H2O
The coefficients are 1, 8, 5,6
Explanation:
The equation for the reaction is given below:
C5H12 + O2 —> CO2 + H2O
Now let us balance the equation. This is illustrated below:
There are 5 atoms of C on the left side and 1atom on the right side. It can be balance by putting 5 in front of CO2 as illustrated below:
C5H12 + O2 —> 5CO2 + H2O
There are 12 atoms of H on the left side and 2atoms on the right. It can be balance by putting 6 in front of H2O as illustrated below:
C5H12 + O2 —> 5CO2 + 6H2O
There are a total of 16 atoms of O on the right side and 2atoms on the left side. It will be balance by putting 8 in front of O2 as illustrated below:
C5H12 + 8O2 —> 5CO2 + 6H2O
Now we see clearly that the equation is balanced as the number of atoms of the different elements on both sides of the equation are the same.
The coefficients are 1, 8, 5,6
First, calculate the number of moles of sodium present with the given mass,
31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium
It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.
mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2
Then, at STP, 1 mol of gas = 22.4 L.
volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L
Answer: 15.34 L
Answer:
Explanation:
Write the balance chemical equation ,
initial concenration of
lets assume that degree of dissociation=
concenration of each component at equilibrium:
as is very small then we can neglect
therefore ,
Eqilibrium concenration of
<span>
Answer: <u>Molarity of solution is 0.751 M. </u>
Reason:
Given: weight of solute (LiF) = 17.8 g, volume of solution = 915 ml = 0.915 l
We know that,
Molarity = </span>
<span>
<em>Molecular Weight of LiF = 25.9 g/mol. </em>
</span>∴<span>,
Molarity = </span>
<span> =
0.751 M</span>