Complete question:
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?
Answer:
The average intensity of the light is 0.02 W/m²
Explanation:
Given;
Amplitude of the electric field, E₀ = 3.78 V/m
The average intensity of the light is calculated as follows;

where;
is the average intensity of the light
c is speed of light = 3 x 10⁸ m/s

Therefore, the average intensity of the light is 0.02 W/m²
Answer:
It relaxes
Explanation:
I took the test I hope it helps
The answer is marine west coast, humid subtropical and Mediterranean. <span />
Answer:
0 N/C
Explanation:
Parameters given:




The distance between
and
is

Electric field is given as

r = 15/2 = 7.5cm = 0.075m
The electric field at their midpoint due to
is:

= 
The electric field at the midpoint due to
is:

= 
The net electric field will be:
E =
+ 
E =
+ 
E = 0 N/C