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Nookie1986 [14]
3 years ago
14

Here is a picture showing how two magnets will stick to one another when opposite poles align. When these magnets are pulled

Physics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

A

Explanation:

The others are only when the poles are the same as in south pole and south pole however north pole and south pole do connect cause they are oppisites

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In this schematic, the total resistance is 50 ohms. 100 ohms. 1,000 ohms. 100 ohms 10,000 ohms
Mrrafil [7]

The total resistance of the given circuit is if the circuit contains 100ohms,1000 ohms,100 ohms and 10,000 ohms resistors.

Resistance is measured in ohms, and it is represented by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who concentrated on the connection between voltage, current and resistance. He is credited for planning Ohm's Regulation.

Resistance estimations are regularly taken to demonstrate the state of a part or a circuit.

  • The higher the resistance, the lower the ongoing current. On the off chance that strangely high, one potential reason (among many) could be harmed guides because of consuming or erosion.
  • The lower the obstruction, the higher the ongoing stream. Potential causes: protectors harmed by dampness or overheating.

Since resistors are connected in series, so we know that when resistors are connected in series, total resistance is given by the formula

Rₙ=R₁+R₂+R₃+---------------Rₙ

So, resistors value are 50 ohms. 100 ohms. 1,000 ohms. 100 ohms 10,000 ohms.

Therefore, total resistance is 50+100+1000+100+10000=10250ohm

Hence, total resistance is 10250ohm

To know more about resistance, visit here:

brainly.com/question/29427458

#SPJ4

4 0
1 year ago
Why can't you feel rhe force of attraction between you and mars
NISA [10]
Because Mars is too far away for its gravitational pull to affect us, in addition Earths gravitational pull is greater than Mars anyways. 
4 0
3 years ago
Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False
kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

\vec{L} = I \vec{\omega}

where I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2 is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2} so \vec{\omega} \neq 0 unless \vec{r} ║  \vec{v}.

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

7 0
3 years ago
What is the period of a wave that has a frequency of 300 hz?
Butoxors [25]

Answer:

T = 0.003 s

(Period is written as T)

Explanation:

Period = time it takes for one wave to pass (measured in seconds)

frequency = number of cycles that occur in 1 second

(measured in Hz / hertz / 1 second)

Period : T

frequency : f

So, if we know that the frequency of a wave is 300 Hz, we can find the period of the wave from the relation between frequency and period

T =  \frac{1}{f}    f = \frac{1}{T}

to find the period (T) of this wave, we need to plug in the frequency (f) of 300

T = \frac{1}{300}

T = 0.00333333333

So, the period of a wave that has a frequency of 300 Hz is 0.003 s

[the period/T of this wave is 0.003 s]

3 0
2 years ago
The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?
Anit [1.1K]

Answer:

The  value is   Q_{net} =  1.239 *10^{-6} \  C

Explanation:

From the question we are told that

   The electric flux is \Phi =  1.4*10^{5} \  N\cdot m^2/C

     

Generally the net charge is mathematically represented as

    Q_{net} =  \Phi *  \epsilon_o

Here \epsilon_o is the permetivity of free space with value  

       \epsilon_o =  8.85*10^{-12}  \  \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

So

   Q_{net} =  1.4*10^5 *  8.85*10^{-12}

=>   Q_{net} =  1.239 *10^{-6} \  C

8 0
3 years ago
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