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Nezavi [6.7K]
3 years ago
7

Match these items. 1. Ca 6 proton 2. H 2O 3 fission 3. nuclear decay 7 element 4. nuclear synthesis 8 electron 5. η atomic numbe

r 6. positive charge compound 7. e neutron 8. number of protons in nucleus fusion NEXT QUESTION ASK FOR HELPTURN IT IN © 2014 Glynlyon, Inc. All rights reserved. TERMS OF USE
Physics
1 answer:
Gnesinka [82]3 years ago
6 0

1. Ca → Element

2. Proton → positive

3. H2O → compound

4. Fission → nuclear decay

5. Fusion → Nuclear synthesis

6. η → Neutron

7. e → electron

8. Atomic number → no of protons in nucleus.

Explanation

1. Ca (Calcium):

Calcium is an element with the atomic number of 20. It is an alkaline earth metal. The 99% of calcium is found in our bodies, in bones, teeth.

2. Proton:

Proton is a subatomic particle and it holds the positive charge. Proton is present in the nucleus of the atom.

3. H2O (water):

Water is a chemical compound and it's chemical formula is H2O. It's called compound as it contains 2 hydrogen and 1 oxygen atoms bonded together through the covalent bond.

4. Fission:

Fission is a process in which large massive unstable nucleus splits into the smaller, less heavier and stable nuclei. The energy is re;eased in the form of radiations during this process. It's called as the radioactive decay.

5. Fusion:

Fusion is opposite of the fission reaction. As in this case the two nuclei combines to form a single large nucleus. That's why it is a nuclear synthesis process.

6. η neutron:

Neutron is a subatomic particle and it is a neutral particle which is located inside the nucleus. n is a symbol used for the neutron.

7. e Electron:

The symbol for electron is e. It's a subatomic particle with negative charge. It is found in the orbits around the nucleus.

8.  Atomic Number:

Atomic number is defined as the number of protons in the nucleus of an atom. IT is represented by Z.

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Answer:

Therefore the ratio of diameter of the copper to that of the tungsten is

\sqrt{3} :\sqrt{10}

Explanation:

Resistance: Resistance is defined to the ratio of voltage to the electricity.

The resistance of a wire is

  1. directly proportional to its length i.eR\propto l
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Therefore

R=\rho\frac{l}{A}

ρ is the resistivity.

The unit of resistance is ohm (Ω).

The resistivity of copper(ρ₁) is 1.68×10⁻⁸ ohm-m

The resistivity of tungsten(ρ₂) is 5.6×10⁻⁸ ohm-m

For copper:

A=\pi r_1^2 =\pi (\frac{d_1}{2} )^2

R_1=\rho_1\frac{l_1}{\pi(\frac{d_1}{2})^2 }

\Rightarrow (\frac{d_1}{2})^2=\rho_1\frac{l_1}{\pi R_1 }......(1)

Again for tungsten:

R_2=\rho_2\frac{l_2}{\pi(\frac{d_2}{2})^2 }

\Rightarrow (\frac{d_2}{2})^2=\rho_2\frac{l_2}{\pi R_2 }........(2)

Given that R_1=R_2   and    l_1=l_2

Dividing the equation (1) and (2)

\Rightarrow\frac{ (\frac{d_1}{2})^2}{ (\frac{d_2}{2})^2}=\frac{\rho_1\frac{l_1}{\pi R_1 }}{\rho_2\frac{l_2}{\pi R_2 }}

\Rightarrow( \frac{d_1}{d_2} )^2=\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}   [since R_1=R_2   and    l_1=l_2]

\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{1.68\times 10^{-8}}{5.6\times 10^{-8}}}

\Rightarrow( \frac{d_1}{d_2} )=\sqrt{\frac{3}{10}}

\Rightarrow d_1:d_2=\sqrt{3} :\sqrt{10}

Therefore the ratio of diameter of the copper to that of the tungsten is

\sqrt{3} :\sqrt{10}

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A factory worker pushes a 30.0-kg crate a distance of 4.5 m along a level floor at constant velocity by pushing horizontally on
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The crate moves at constant velocity, this means that its acceleration is zero, so the net force acting on the crate is zero (Newton's second law). 

There are only two forces acting on the crate: the force F applied by the worker and the frictional force, acting in the opposite direction: \mu m g, where \mu=0.25 is the coefficient of friction and m=30.0 kg is the mass of the crate. Since the net force should be equal to zero, the two forces must have same magnitude, so we have:
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A scientist pours grape juice on three identical white shirts. He then uses three different cleaning products on the shirts and
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Answer:

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Explanation:

Magnetic field is along z axis while velocity is in x-z plane

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F = q(\vec v \times \vec B)

so here we can say

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So due to this component of motion it will move along a circle while other component of the motion will remain uniform always

So here it is combination of two parts

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