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kozerog [31]
2 years ago
8

A current of 0. 82 a flows through a light bulb. how much charge passes through the light bulb during 94 s?

Physics
1 answer:
gladu [14]2 years ago
4 0

A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C

The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.

The relation between the charge, current and time is given as:

Q = I × t

where, Q is the charge flown through bulb

I is the current passed through bulb

t is the time for which charge passes through bulb

Given,

I = 0.82A

t = 94s

Q = ?

Substituting the values in the above formula:

Q = I × t

Q = 0.82 × 94

Q = 77.08C

Hence, The charge passed through the light bulb during 94 s is 77.08C

Learn more about Current here, brainly.com/question/2264542

#SPJ4

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8 0
3 years ago
An object begins at position x = 0 and moves one-dimensionally along the x-axis witļi a velocity v
Liula [17]

Answer:

The answer is "between 20 s and 30 s".

Explanation:

Calculating the value of positive displacement:

\ (x_{+ve}) = \frac{1}{2} \times 15 \times  20 \\\\

          = \frac{1}{2} \times 300 \\\\=  150 \\\\

Calculating the value of negative displacement upon the time t:

(x_{-ve}) = \frac{1}{2} \times 5 \times 20- 20(t-20) \\\\

          = \frac{1}{2} \times 100- 20t+ 400 \\\\= 50- 20t+ 400 \\\\

\to X= X_{+ve} + X_{-ve} \\\\

\to  150 - 50 -20t+400 =0\\\\\to 100 -20t+400 =0 \\\\\to 500 -20t =0\\\\\to 20t =500 \\\\\to t=\frac{500}{20}\\\\\to t=\frac{50}{2}\\\\\to t= 25

That's why its value lie in "between 20 s and 30 s".

6 0
4 years ago
A parallel-plate capacitor has circular plates of 7.10 cm radius and 1.26 mm separation. What charge (in nC) will appear on the
erik [133]

Answer:

13.98 nC

Explanation:

Capacitance depends upon the area of the plates and their distance of separation.

Radius = r = 0.071 m

separation = d = 0.00126 m

C = \frac{\kappa  \epsilon _{o} A }{d}

here κ = 1 and ε₀ = 8.85 ₓ 10⁻¹² SI units , for free space.

Area = A = π r² = 0.0158 m²

C = [( 8.85 ₓ 10⁻¹² ) ( 0.0158) ]÷ (0.00126) = 1.11 x 10⁻¹⁰ F

Charge = Q = C V = ( 1.11 x 10⁻¹⁰ F )(126) = 13.98 nC

                   = 14 nC ( rounded to two significant digits)

6 0
3 years ago
Is the the last half of the month waxing or waning( talking about moon phases
rewona [7]
Its not really definable. Say, you can have a full moon on the last day of November, and have the waning phases throughout the first half. Or you can have a new moon on the last day of December, and have the waxing phases during the first half of the month.
\
5 0
3 years ago
Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to report the mass truthfully). (a) W
bija089 [108]

Answer:

1411.8 N/m

Explanation:

From Hooke's law;

F= Ke

Where

F= force on the spring

K= force constant

e = extension

But e= 8.50 × 10^-2m

F= weight = 12.0 kg × 10 = 120 N

K = F/e = 120/8.50 × 10^-2

K= 1411.8 N/m

7 0
3 years ago
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