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kozerog [31]
1 year ago
8

A current of 0. 82 a flows through a light bulb. how much charge passes through the light bulb during 94 s?

Physics
1 answer:
gladu [14]1 year ago
4 0

A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C

The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.

The relation between the charge, current and time is given as:

Q = I × t

where, Q is the charge flown through bulb

I is the current passed through bulb

t is the time for which charge passes through bulb

Given,

I = 0.82A

t = 94s

Q = ?

Substituting the values in the above formula:

Q = I × t

Q = 0.82 × 94

Q = 77.08C

Hence, The charge passed through the light bulb during 94 s is 77.08C

Learn more about Current here, brainly.com/question/2264542

#SPJ4

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If there is an object in top of another object, why does the upper object exert a downward normal force?​
rusak2 [61]

Answer:

This is because normal force is exerted perpendicularly to the point of contact between the upper and lower objects.  

Explanation:

This is because the upper object is still subject to gravitational pull. Therefore, the amount of force it exerts on the lower object due to gravity will be equal to the normal force that acts in the negative direction of gravitational force. Additionally, normal force is evident because the upper object will not go into the lower object.

4 0
3 years ago
Which of the following is incorrect for nuclear forces
densk [106]

Answer:

c they obey inverse square law

4 0
2 years ago
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what principle is responsible for alternating light and dark bands when light passes through two or more narrow slits?
olya-2409 [2.1K]

The superposition principle is responsible for alternating light and dark bands when light passes through two or more narrow slits.

The intensity pattern that appears on the lit screen is determined by the superposition principle. When the difference in pathways from the two slits to a location on the screen equals an integral number of wavelengths (0,λ,2λ ,...), constructive interference takes place.

The fact that the two waves' crests follow different paths ensures that they do. A distinctive pattern of brilliant and dark fringes is seen when monochromatic light illuminates a distant screen after passing through two small openings. The superposition of overlapping light waves coming from the two slits results in this interference pattern.

Learn more about superposition principle here;

brainly.com/question/2699638

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7 0
1 year ago
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d
Mnenie [13.5K]

Answer:

(C) 40m/s

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0
2 years ago
When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people
Tanzania [10]

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout \beta _{1}=58.4dB

When n number of person shout together \beta _{n}=102dB

The sound intensity level during one person shout is given by:

\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}

The sound intensity level during n number of person shout is given by:

\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}

Since each person generates same sound intensity and hence total number  of persons can be determined as

 =\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909

Hence

The number of people at game are approximately 22909

3 0
3 years ago
Read 2 more answers
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