Answer:
<em>The second ball has four times as much kinetic energy as the first ball.</em>
Explanation:
<u>Kinetic Energy
</u>
Is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
![\displaystyle K=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
Where:
m = mass of the object
v = speed at which the object moves
The kinetic energy is expressed in Joules (J)
Two tennis balls have the same mass m and are served at speeds v1=30 m/s and v2=60 m/s.
The kinetic energy of the first ball is:
![\displaystyle K_1=\frac{1}{2}m\cdot 30^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_1%3D%5Cfrac%7B1%7D%7B2%7Dm%5Ccdot%2030%5E2)
![\displaystyle K_1=\frac{1}{2}m\cdot 900](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_1%3D%5Cfrac%7B1%7D%7B2%7Dm%5Ccdot%20900)
![K_1=450m](https://tex.z-dn.net/?f=K_1%3D450m)
The kinetic energy of the second ball is:
![\displaystyle K_2=\frac{1}{2}m\cdot 60^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_2%3D%5Cfrac%7B1%7D%7B2%7Dm%5Ccdot%2060%5E2)
![\displaystyle K_2=\frac{1}{2}m\cdot 3600](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_2%3D%5Cfrac%7B1%7D%7B2%7Dm%5Ccdot%203600)
![K_2=1800m](https://tex.z-dn.net/?f=K_2%3D1800m)
Being m the same for both balls, the second ball has more kinetic energy than the first ball.
To find out how much, we find the ratio:
![\displaystyle \frac{K_2}{K_1}=\frac{1800m}{450m}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BK_2%7D%7BK_1%7D%3D%5Cfrac%7B1800m%7D%7B450m%7D)
Simplifying:
![\displaystyle \frac{K_2}{K_1}=4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BK_2%7D%7BK_1%7D%3D4)
The second ball has four times as much kinetic energy as the first ball.
D make one revolution around the sun hope this helps
Answer:
Approximately
.
Explanation:
It is given that
and
are connected in a circuit in parallel.
Assume that this circuit is powered with a direct current power supply of voltage
.
Since
and
are connected in parallel, the voltage across the two resistors would both be
. Thus, the current going through the two resistors would be
and
, respectively.
Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor:
.
In other words, if the voltage across this circuit is
, the total current in this circuit would be
. The (equivalent) resistance
of this circuit would be:
.
Given that
and
:
.
Answer:
1. Dry Beans - 591.75 kg/m^3
2. Flour - 593 kg/m^3
3. Wax - 900 kg/m^3
4. Wet sand - 2039 kg/m^3
5. Chalk - 2499 kg/m^3
6. Talcum Powder - 2776 kg/m^3
7. Copper - 8960 kg/m^3
Explanation:
Make sure your units are the same