Answer:
A voltage-controlled resistor (VCR) is a three-terminal active device with one input port and two output ports. The input-port voltage controls the value of the resistor between the output ports. VCRs are most often built with field-effect transistors (FETs). Two types of FETs are often used: the JFET and the MOSFET.
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The displacement is a vector that is calculated by subtracting the final and initial positions of an object that has made a movement.
We know that initially the object was at the origin and moved to the -8m position.
Suppose that the movement was made on the x-axis. So:
d = [-8 - (0)]x
d = -8x
Regarding the second question.
When the acceleration is constant then the speed changes at a constant rate. Therefore the graph of velocity vs. time will look like a line with a negative slope (if the acceleration is negative) or a line with a positive slope (if the acceleration is positive)
For example. Suppose that the acceleration of gravity is 10
Now suppose you drop an object from a building.
At the initial moment (second 0) the speed is 0 m/s.
After 1 second the speed of the object will be 10 m/s.
After 2 seconds the speed of the object will be 20 m/s.
After 4 seconds the speed will be 40 m/s.
The graph of this example is shown in the attached figure. Note that it is a straight line.
Explanation:
Given that,
Mass of the cart,
Mass of the cart 2,
Final speed of cart 2,
Final speed of cart 1 is 0 as it comes to rest.
Let us assume that the initial velocity of the cart 2 is 0. So using the conservation of linear momentum as :
So, the initial velocity of the 1.0-kg cart is 0.9 m/s.
Answer:
If we assume that the box is a cube with 150 m² surface area
Area of 1 face = 150 m² / 6 = 25 m²
The box will exert a downward force of
Force = mass * acceleration due to gravity
Force = 300 kg * 9.81 m/s² N
Force = 2943 N
The box exerts a pressure ( force / unit area) = 2943 N / 25 m²
Pressure = 117.7 N/m²
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Answer: h = 20.92 m
Explanation: By using the law of conservation of energy, the kinetic energy of the ball equals it potential energy.
Kinetic energy =mv^2/2
Potential energy = mgh
Where m = mass of the object, v = velocity of object = 23.5 m/s
g = acceleration due gravity = 9.8 m/s^2
mv^2/2 = mgh
m cancels out each other on both sides , hence we have that
v^2 = 2gh.
We want the ball to move towards the wall (horizontal motion), hence we need the horizontal component of the velocity since the velocity is inclined at an angle of 30.5 to the ground (horizontal).
Hence v = 23.5 × cos 30.5, v = 20.248 m/s
Recall that v^2 = 2gh
(20.248)^2 = 2×9.8×h
409.98 = 19.6 h
h = 409.98/ 19.6
h = 20.92 m