In this problem, we are given with the resultant velocity of the swimmer considering the current is running 0.91 m/s that is equal to 1.1 m/s2. In this case, using v = d/t, t = 3000m / 1.1 m/s equal to 2727.27 seconds equal to 45.45 hours. The distance downstream is equal to 2727.27 seconds * 0.91 m/s equal to 2481.82 meters.
Answer:
Her displacement is 35 feet. Her distance is 75 feet.
If she walks 20 ft N, 35 ft E, and 20 ft S, it makes a rectangle with one missing side, which is 35. Her displacement is therefore 35, and 20 plus 35 plus 20 equals 75, which is the distance she walked.
Hope this helps!
This isn’t anything related to physics dude
Answer:
The force required to hold the contraction in place is 665.91 N ↑
Explanation:
Given;
specific gravity of oil, γ = 0.75
Volumetric flow rate, V 3.2 Ft³/s = 0.0906 m³/s
where;
is the density of oil
is the density of water = 1000 kg/m³
∴density of oil () = γ × density of water()
= 0.75 × 1000 kg/m³
= 750kg/m³
Buoyant Force = ρVg
= 750 × 0.0906 × 9.8
= 665.91 N ↑
This force acts upward or opposite gravitational force.
Therefore, the force required to hold the contraction in place is 665.91 N ↑
