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3 years ago

If 2.00 g of Zn is allowed to react with 2.00 g of CuSO4, how many grams of

Chemistry

2 answers:

otez555 [7]3 years ago

8 0

Answer:

Explanation:

valentinak56 [21]3 years ago

7 0

Answer:

1.1445g

Explanation:

Mass of Zn = 2.0g

Mass of CuSO4 = 2.0g

Molar mass of Zn = 65.4g/mol

Molar mass of CuSO4 = 159.5g/mol

No. Of moles = mass / molar mass

No. Of moles of Zn = 2.0/65.4 = 0.030moles

No. Of moles of CuSO4 = 2/159.5 = 0.0125 moles

Equation of reaction

CuSO4 (aq) +Zn(s)-> ZnSO4(aq) + Cu(s)

Stoichiometric molar ratio of CuSo4 : Zn = 1:1

Actual molar ration of CuSO4 : Zn = ?

0.0125 / 0.030 = 1 / 2.4

Zn is present in excess in the reaction, while CuSO4 is the limiting reagent

1 mol of CuSO4 = 1 mol of Zn

0.0125 moles of CuSO4 = 0.0125 moles of Zn

No. Of moles left after reaction = 0.030 - 0.0125 = 0.0175 moles.

Mass = no. Of moles * molar mass = 0.0175 * 65.4 = 1.1445g

The mass of Zn left after the reaction is 1.1445g.

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Ocean waves contain tremendous energy potential. Wave power devices extract energy directly from the surface motion of ocean waves. In many areas of the world, the wind blows with enough consistency and force to provide continuous waves along the shoreline.

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3 years ago

Which explains how burning a magnesium ribbon highlights a toolmark?

Setler [38]

<h2>Answer:</h2>

The magnesium ribbon, <u>D. It forms a material to cast the tool mark</u>.

<h2>Explanation:</h2>

When a magnesium ribbon is burnt in the presence of oxygen it gives out strong light and heat is produced. Apart from it, it leads to the production of substance called as magnesium oxide which is formed as the product due to the reaction of magnesium with the oxygen present in the air.

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6 0

3 years ago

4. Explain what you’ve learned about significant figures. How many significant figures are in the measurement 0.03050 kg?

nasty-shy [4]

There are 4 significant figures! Start counting after the first non-zero digit :)

Hope this helps.

3 0

3 years ago

Can I please Get Help with this question ‍♂️ ?

Nitella [24]

Answer:

Mg(NO4)2 is 180.3 g/mol

Explanation:

First find the substance formula.

Magnesium Nitrate.

Magnesium is a +2 charge.

Nitrate is a -1 charge.

So to balance the chemical formula,

We need 1 magnesium atom for every nitrate atom.

2(1) + 1(-2) = 0

So the substance formula is Mg(NO4)2.

Now find the molar mass of Mg(NO4)2.

Mg = 24.3 amu

N = 14.0 amu

O = 16.0 amu

They are three nitrogen and twelve oxygen atoms.

So you do this: 24.3 + 14.0(2) + 16.0(8) = 180.3 g/mol

So the molar is mass is 180.3 g/mol.

The final answer is Mg(NO4)2 is 180.3 g/mol

Hope it helped!

7 0

3 years ago

A buffer contains 0.18 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH

Yuki888 [10]

Answer:

1) pH = 5.05

2) pH = 5.13

3) pH = 4.97

Explanation:

Step 1: Data given

Number of moles of propionic acid = 0.18 moles

Number of moles sodium propionate = 0.26 moles

Volume = 1.20 L

Ka = 1.3 * 10^-5 → pKa = 4.989

Step 2: Calculate concentrations

Concentration = moles / volume

[acid]= 0.18/ 1.2 =0.150 M

[salt]= 0.26/ 1.3 = 0.217 M

pH = 4.89 + log(0.217/0.150)=<u>5.05</u>

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What is the pH of the buffer after the addition of 0.02 mol of NaOH?

moles acid = 0.18 - 0.02 = 0.16

[acid]= 0.16/ 1.2=0.133 M

moles salt = 0.26 + 0.02 = 0.28

[salt]= 0.28/ 12=0.233

pH = 4.89 + log 0.233/ 0.133 = 5.13

What is the pH of the buffer after the addition of 0.02 mol of HI?

moles acid = 0.18+ 0.02 = 0.20 moles

[acid]= 0.20/ 1.2 = 0.167 M

[salt]= 0.26 - 0.02= 0.24 moles

[salt]= 0.24/ 1.2 = 0.20 M

pH = 4.89 + log 0.20/ 0.167= 4.97

8 0

3 years ago