Answer:
1.1445g
Explanation:
Mass of Zn = 2.0g
Mass of CuSO4 = 2.0g
Molar mass of Zn = 65.4g/mol
Molar mass of CuSO4 = 159.5g/mol
No. Of moles = mass / molar mass
No. Of moles of Zn = 2.0/65.4 = 0.030moles
No. Of moles of CuSO4 = 2/159.5 = 0.0125 moles
Equation of reaction
CuSO4 (aq) +Zn(s)-> ZnSO4(aq) + Cu(s)
Stoichiometric molar ratio of CuSo4 : Zn = 1:1
Actual molar ration of CuSO4 : Zn = ?
0.0125 / 0.030 = 1 / 2.4
Zn is present in excess in the reaction, while CuSO4 is the limiting reagent
1 mol of CuSO4 = 1 mol of Zn
0.0125 moles of CuSO4 = 0.0125 moles of Zn
No. Of moles left after reaction = 0.030 - 0.0125 = 0.0175 moles.
Mass = no. Of moles * molar mass = 0.0175 * 65.4 = 1.1445g
The mass of Zn left after the reaction is 1.1445g.
