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3 years ago

The energy released by a nuclear fusion reaction is produced when

Chemistry

1 answer:

Igoryamba3 years ago

8 0

Answer:

Explanation:

energy produced in nuclear fusion or even fission is due to mass defect and it can be calculated by Einstein equation e=mc2

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Which of the following is an example of the characteristic of movement?

vagabundo [1.1K]

A. The kitten shivers like she’s cold

those link share ppl are SOOOOOO ANNOYING

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3 years ago

Define the terms heredity and inherited in your own words.

adelina 88 [10]

Answer:

Heredity is when you have gotten either physical or mental traits from your parents.

Inherited in Biology: Getting traits from your parents

Inherited outside Biology: is the practice of passing on private property, titles, debts, privileges, rights, and obligations upon the death of an individual.

Explanation:

3 0

3 years ago

In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce ga

Reptile [31]

Answer:

The rate at which ammonia is being produced is 0.41 kg/sec.

Explanation:

$N_2+3H_2\rightarrow 2NH_3$ Haber reaction

Volume of dinitrogen consumed in a second = 505 L

Temperature at which reaction is carried out,T= 172°C = 445.15 K

Pressure at which reaction is carried out, P = 0.88 atm

Let the moles of dinitrogen be n.

Using an Ideal gas equation:

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.88 atm\times 505 L}{0.0821 atm l/mol K\times 445.15 K}=12.1597 mol$

According to reaction , 1 mol of ditnitrogen gas produces 2 moles of ammonia.

Then 12.1597 mol of dinitrogen will produce :

$\frac{2}{1}\times 12.1597 mol=24.3194 mol$ of ammonia

Mass of 24.3194 moles of ammonia =24.3194 mol × 17 g/mol

=413.43 g=0.41343 kg ≈ 0.41 kg

505 L of dinitrogen are consumed in 1 second to produce 0.41 kg of ammonia in 1 second. So the rate at which ammonia is being produced is 0.41 kg/sec.

6 0

3 years ago

Calculate E ° for the half‑reaction, AgCl ( s ) + e − − ⇀ ↽ − Ag ( s ) + Cl − ( aq ) given that the solubility product constant

antoniya [11.8K]

Answer: The value of $E^{o}$ for the half-cell reaction is 0.222 V.

Explanation:

Equation for solubility equilibrium is as follows.

$AgCl(s) \rightleftharpoons Ag^{+}(aq) + Cl^{-}(aq)$

Its solubility product will be as follows.

$K_{sp} = [Ag^{+}][Cl^{-}]$

Cell reaction for this equation is as follows.

$Ag(s)| AgCl(s)|Cl^{-}(0.1 M)|| Ag^{+}(1.0 M)| Ag(s)$

Reduction half-reaction: $Ag^{+} + 1e^{-} \rightarrow Ag(s)$ , $E^{o}_{Ag^{+}/Ag} = 0.799 V$

Oxidation half-reaction: $Ag(s) + Cl^{-}(aq) \rightarrow AgCl(s) + 1e^{-}$ , $E^{o}_{AgCl/Ag}$ = ?

Cell reaction: $Ag^{+}(aq) + Cl^{-}(aq) \rightarrow AgCl(s)$

So, for this cell reaction the number of moles of electrons transferred are n = 1.

Solubility product, $K_{sp} = [Ag^{+}][Cl^{-}]$

= $1.77 \times 10^{-10}$

Therefore, according to the Nernst equation

$E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}$

At equilibrium, $E_{cell}$ = 0.00 V

Putting the given values into the above formula as follows.

$E_{cell} = E^{o}_{cell} - \frac{0.0592 V}{n} log \frac{[AgCl]}{[Ag^{+}][Cl^{-}]}$

$0.00 = E^{o}_{cell} - \frac{0.0592 V}{1} log \frac{1}{[Ag^{+}][Cl^{-}]}$

$E^{o}_{cell} = \frac{0.0592}{1} log \frac{1}{K_{sp}}$

= $0.0591 V \times log \frac{1}{1.77 \times 10^{-10}}$

= 0.577 V

Hence, we will calculate the standard cell potential as follows.

$E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}$

$0.577 V = E^{o}_{Ag^{+}/Ag} - E^{o}_{AgCl/Ag}$

$0.577 V = 0.799 V - E^{o}_{AgCl/Ag}$

$E^{o}_{AgCl/Ag}$ = 0.222 V

Thus, we can conclude that value of $E^{o}$ for the half-cell reaction is 0.222 V.

3 0

3 years ago

4.2 g of lithium (Li) reacts with 2.8 g of nitrogen (N2). Find the simplest molar ratio in which lithium reacts with nitrogen.

o-na [289]

The simplest molar ratio in which lithium reacts with nitrogen is 6 moles of lithium to 1 mol of nitrogen.

What is molar ratio?

A molar ratio examines the ratio that exist between two chemical compounds showing the amounts in moles of the compounds involved in a chemical reaction.

Molar ratio = amount of a constituent in moles ÷ total amount of all constituents in a mixture in moles

Given:

Mass of lithium (Li) = 4.2 g

Mass of nitrogen (N2) = 2.8 g

Total amount of mass = 7g

Moles = molecular weight ÷ mass of water

Moles of lithium (Li) = 4.2 ÷ 7 = 0.60 mol

Moles of nitrogen (N₂) = 2.8 ÷ 7 = 0.10 mol

Therefore, ratio Li : N₂ = 0.60 : 0.10 = 6 : 1

6 Li + N₂

The balanced equation between lithium and nitrogen, to form lithium nitride = 6 Li + N₂ → 2 Li₃N₆L i + N₂ → 2Li₃N

In summary, the simplest molar ratio in which lithium reacts with nitrogen is 6:1

Learn more about molar ratio here: brainly.com/question/14677248

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8 0

1 year ago