Ask question

Ask question

All categories

3 years ago

9

Please answer the question asked in the image.

1 answer:

Naddika [18.5K]3 years ago

8 0

Answer:

you are a noob bro ok or not

You might be interested in

A coiled spring with coils that are closely spaced then widely then closely then widely then closely, ending with a yellow line

liberstina [14]

Answer:

2, sorry I'm late but my answer is right, I just took the quiz

4 0

3 years ago

Read 2 more answers

70-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 844 N. What is the acceleration o

mario62 [17]

Answer : The acceleration of the elevator is, $2.25m/s^2$

Explanation :

Formula used to calculate the acceleration of the elevator is:

$F=mg+ma\\\\ma=F-mg\\\\a=\frac{F-mg}{m}$

where,

F = force = 844 M

m = mass of man = 70 kg

g = acceleration due to gravity = $9.8m/s^2$

a = acceleration of the elevator = ?

Now put all the given values in the above formula, we get:

$a=\frac{F-mg}{m}$

$a=\frac{844N-(70kg\times 9.8m/s^2)}{70kg}$

$a=2.25m/s^2$

Thus, the acceleration of the elevator is, $2.25m/s^2$

4 0

3 years ago

>En cual de las siguientes situaciones la fuerza neta sobre el cuerpo es cero?

ExtremeBDS [4]

La respuesta es "Un avion que vuela al norte con rapidez constante y altitud constante".

Para que la fuerza neta sea 0, la aceleracion debe ser 0, para esto la velocidad debe ser constante.

Para que la velocidad sea constante el objecto debe estar moviendo con rapidez (magnitud de la velocidad) constante y sin cambiar direccion; ya que la velocidad es un vector asi es que depende en magnitud y direccion.

En las demas opciones la magnitud de la velocidad (rapidez) cambia y/o la direccion.

3 0

3 years ago

Water is to be boiled at sea level (1 atm pressure) in a 30-cm-diameter stainless steel pan placed on top of a 18-kW electric bu

Tamiku [17]

Answer:

Explanation:

18 kW = 18000 J /s

60% of 18kW = 10800 J/s

Latent heat of evaporation of water

= 2260 x 10³ J / kg

kg of water being evaporated per second

= 10800 / 2260 x 10³ kg /s

= 4.7787 x 10⁻³ kg / s

= 4.78 gm / s .

3 0

3 years ago

Suppose that a 102.5 kg football player running at 8.5 m/s catches a 0.47 kg ball moving at a speed of 22.5 m/s with his feet of

nadya68 [22]

Answer:

a) $v=8.564\ m.s^{-1}$

b) $\Delta KE=45.76\ J$

c) $v=8.358\ m.s^{-1}$

d) $\Delta KE=225.24\ J$

Explanation:

Given:

mass of the player, $m_p=102.5\ kg$

mass of the ball, $m_b=0.47\ kg$

initial velocity of the player, $v_p=8.5\ m.s^{-1}$

initial velocity of the ball, $v_b=22.5\ m.s^{-1}$

a)

<u>Case:</u> When the player and the ball are moving in the same direction.

$m_t.v=m_p.v_p+m_b.v_b$

where:

$m_t=$ total mass after the player catches the ball

v = final velocity of the system

$v=\frac{102.5\times 8.5+0.47\times 22.5}{(102.5+0.47)}$

$v=8.564\ m.s^{-1}$

b)

Initial kinetic energy of the system:

$KE_i=\frac{1}{2} [m_p.v_p^2+m_b.v_b^2]$

$KE_i=\frac{1}{2} [102.5\times 8.5^2+0.47\times 22.5^2]$

$KE_i=3821.78\ J$

Final kinetic energy of the system:

$KE_f=\frac{1}{2} m_t.v^2$

$KE_f=\frac{1}{2}\times 102.97\times 8.564^2$

$KE_f=3776.02\ J$

∴Change in kinetic energy

$\Delta KE=KE_i-KE_f$

$\Delta KE=3821.78-3776.02$

$\Delta KE=45.76\ J$

c)

<u>Case:</u> When the player and the ball are moving in the opposite direction.

$m_t.v=m_p.v_p-m_b.v_b$

$v=\frac{102.5\times 8.5-0.47\times 22.5}{(102.5+0.47)}$

$v=8.358\ m.s^{-1}$

d)

Final kinetic energy in this case:

$KE_f=\frac{1}{2} m_t.v^2$

$KE_f=0.5\times 102.97\times 8.358^2$

$KE_f=3596.54\ J$

∴Change in kinetic energy:

$\Delta KE=KE_i-KE_f$

$\Delta KE=3821.78-3596.54$

$\Delta KE=225.24\ J$

3 0

3 years ago