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Colt1911 [192]
3 years ago
9

Please answer the question asked in the image.

Physics
1 answer:
Naddika [18.5K]3 years ago
8 0

Answer:

you are a noob bro ok or not

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How much work (MJ) must a car produce to drive 125 miles if an average force of 306 N must be maintained to overcome friction?
baherus [9]

Answer:

The right solution is "61.557 MJ". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 306 N

Drive,

D = 125 miles,

i.e.,

  = 201168

meters

As we know,

The work done will be:

= F\times S

On substituting the given values, we get

= 306\times 201168

= 61557408 \ J

On converting it in "MJ", we get

= 61.557\times 10^6 \ J

= 61.557 \ MJ

6 0
3 years ago
A steel wire of length 3.0cm is stretched through 2mm. If the cross-sectional
yarga [219]

Explanation:

rigidibiyu. jtibiti vekov oeo i irki jri kri oro lro

8 0
3 years ago
An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m
ddd [48]

Answer:

Velocity of electron will be 1.325\times 10^6m/sec

Explanation:

We have given distance across the plate d = 2 mm =2\times 10^{-3}m

Potential difference V = 6 volt

We know that potential difference at any distance is given by

V = Ed , here V is potential difference, E is electric field and d  is distance

So E=\frac{V}{d}=\frac{6}{2\times 10^{-3}}=3000N/C

Charge on electron e=1.6\times 10^{-19}C

We know that expression of velocity is given by v=\sqrt{\frac{2qEd}{m_e}}, here q is charge on electron, E is electric field and d is distance

So v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 3000\times 3000}{9.11\times 10^{-31}}}=1.325\times 10^6m/sec

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4 years ago
Join my me et.gogle .etj-dovn-kds​
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Sweet, Hold On I just need to download le app

5 0
3 years ago
Olivia places her pet frog on a line to observe the frog motion. The line is divided into sections that measure 1 centimeter eac
Goshia [24]
There is no displacement. The frog is back where it began.
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4 years ago
Read 2 more answers
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