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Olaf’s little snowman friends are taking a ride in a sled. The mass of the sled and the little snowmen is 300kg. Olaf realizes t

OverLord2011 [107]

Answer:

A I think I hope this helps you out!

6 0

3 years ago

Is it safe to drive your 1600-kg car at speed 34 m/s around a level highway curve of radius 190 m if the effective coefficient o

adoni [48]

Answer:

It is unsafe

Explanation:

v = Velocity of car = 34 m/s

r = Radius of turn = 190 m

$\mu$ = Coefficient of static friction = 0.5

m = Mass of car = 1600 kg

g = Acceleration due to gravity = 9.81 m/s²

The centripetal force is given by

$F_c=m\frac{v^2}{r}\\\Rightarrow F_c=1600\frac{34^2}{190}\\\Rightarrow F_c=9734.73\ N$

The frictional force is given by

$F_f=\mu mg\\\Rightarrow F_f=0.5\times 1600\times 9.81\\\Rightarrow F_f=7848\ N$

If the centripetal force is greater than the frictional force then the car will slip which makes it unsafe.

Here, the centripetal force is greater than the frictional force which makes it unsafe to drive it at that speed.

4 0

3 years ago

An unknown source plays a pitch of middle C (262 Hz). How fast would the sound wave from this source have to travel to raise

Viefleur [7K]

Answer:

The sound travels at $v_{s}=11.4 \mathrm{m} / \mathrm{s}$

Option: c

Explanation:

Unknown source plays of middle C (fs) = 262 Hz

The sound wave from this source have to travel to raise the pitch to C sharp is (fd) = 272 Hz

$\begin{array}{l}{velocity of sound in air(v)=343 \mathrm{m} / \mathrm{s}, f_{\mathrm{s}}=262 \mathrm{Hz}, f_{\mathrm{d}}=271 \mathrm{Hz}} \\ {velocity of receiver(v_{\mathrm{d}})=0 \mathrm{m} / \mathrm{s},velocity of source( v_{\mathrm{s}}) \text { is unknown }}\end{array}$

$\text { Speed of sound } \mathrm{V}_{\mathrm{S}}=343 \mathrm{m} / \mathrm{s}$

$f_{\mathrm{d}}=f_{\mathrm{s}}\left(\frac{v-v_{\mathrm{d}}}{v-v_{\mathrm{s}}}\right)$

$\frac{f_{d}}{f_{s}}=\left(\frac{v-v_{d}}{v-v_{s}}\right)$

$\left(v-v_{s}\right)=\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)$

$v_{s}=v-\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)$

Substitute the given values in the formula,

$v_{s}=343+\frac{262}{271}(343-0)$

$v_{s}=343+0.966(343)$

$v_{s}=343-331.33$

$v_{s}=11.4 \mathrm{m} / \mathrm{s}$

Therefore, The sound travels at $v_{s}=11.4 \mathrm{m} / \mathrm{s}$

4 0

3 years ago

The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant

almond37 [142]

Answer:

The column of methanol is = 12.27 m high

Explanation:

The pressure of mercury (p) = ghd,................... equation 1

Where g = acceleration due to gravity, h= height, d = density.

d = 13.6 g/ml convert to kg/m³ = 13.6 g/ml(1000 (kg/m³)/(g/ml))

d =13600 kg/m³., h= 713mm = 713/1000 = 0.713 m., g= 9.80 m/s²

Substituting these values into equation 1,

P = 13600 × 0.713 × 9.8 = 95028.64 N/m².

If the pressure of the mercury supports the pressure exerted by the methanol

∴ pressure that supports the mercury = pressure of the methanol

p = ghd

making h the subject of formula,

h = p/gd ........................... equation 2

Where p = 95028.64 N/m², g = 9.8 m/s², d = 0.79 g/ml = (0.79 × 1000) kg/m³

d = 790 kg/m³.

Substituting these values into equation 2

h = 95028.64/(9.8×790)

h = 95028.64/7742

h = 12.27 m.

The column of methanol is = 12.27 m high

7 0

3 years ago

special metal hangers or stirrips called joist hangers are used when joist must be _____ the bottom of the grider or beam

djyliett [7]

Answer:

Special metal hangers or stirrups called joist hangers are used when joist must be flush with the bottom of the girder or beam.

Explanation:

A joist hanger also known as a beam hanger is a mechanical device which is used to fasten joists and rafters.
The rafters are the carried members to beams and headers are the carrying members.

Thus, special metal hangers or stirrups called joist hangers are used when joist must be flush with the bottom of the girder or beam.

Learn more about construction here:

brainly.com/question/14428327

#SPJ4

7 0

2 years ago