To solve this problem, we use Beer's Law: A= ε.l.c
A is the absorbance- 0,558
<span>ε is</span> the molar absorptivity- is <span>15000 </span><span><span>L⋅mol-1</span><span>cm-1</span></span>
<span>l is </span>the length of the cuvette- 1 cm
<span>c is</span> the molar concentration
Applying the formula,
0,558= 15000 x 1 x c
0,558/15000= c
c= <span>3.72×<span>10⁻⁵ </span> <span>mol⋅L<span>⁻¹</span></span></span>
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Hey there: !
density = 19.32 g/cm³
mass = 54.82 g
Volume = ?
therefore:
D = m / V
19.32 = 54.82 / V
V = 54.82 / 19.32
V = 2.837 cm³
Answer:
The volume of nitrogen oxide formed is 35.6L
Explanation:
The reaction of nitric acid with copper is:
Cu(s) + 4HNO₃ → Cu(NO₃)₂ + 2NO₂(g) + 2H₂O(l)
Moles of copper are:
Moles of nitric acid are:
As 1 mol of Cu reacts with 4 moles of HNO₃:
0.697 mol Cu × (4mol HNO₃ / 1mol Cu) = 2.79 moles of HNO₃ will react. That means Cu is limiting reactant.
Moles of NO₂ produced are:
0.697 mol Cu × (2mol NO₂ / 1mol Cu) = <em>1.394 moles of NO₂</em>
Using PV = nRT
<em>Where P is pressure (735torr / 760 = 0.967atm); n are moles (1.394mol); R is gas constant (0.082atmL/molK); T is temperature (28.2°C + 273.15 = 301.35K). </em>
Thus, volume is:
V = nRT / P
V = 1.394mol×0.082atmL/molK×301.35K / 0.967atm
V = 35.6L
<em>The volume of nitrogen oxide formed is 35.6L</em>
Answer:
We expect the enthalpies of combustion of two isomers to be different.
The molecular formular of the two molecules are very similar.
So the balanced chemical equation for the two combustion reactions are the same.
Explanation:
In calculation of the combustion enthalpiesfrom the isomers of the products and reactant.
The difference will be in the standard enthalpies of formation of the two combustion products.
The rod-shaped n- octane has vibrational and rotational motion possible more than the almost spherical neoprene.
I believe it would be C. While D is also a good answer, the question asks for the statement that is most likely true, and there is no absolute guarantee that in 20 years our resource use will be higher than it is now.