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Answer:
Reducing or increasing the amount of H+ ions / hydronium (H3O+) ions
Explanation:
To reduce the pH (reducing the strength of the acid) can be done by adding a base (including a conjugate base such as bicarbonate ion) which will absorb the H+ ions either through adsorption or reaction.
Adding more H+ decreases the pH of the acid making it stronger. This can be done by adding HCL that will dissociate and increase the H+ ions.
Answer:
B. 111 J
Explanation:
The change in internal energy is the sum of the heat absorbed and the work done on the system:
ΔU = Q + W
At constant pressure, work is:
W = P ΔV
Given:
P = 0.5 atm = 50662.5 Pa
ΔV = 4 L − 2L = 2 L = 0.002 m³
Plugging in:
W = (50662.5 Pa) (0.002 m³)
W = 101.325 J
Therefore:
ΔU = 10 J + 101.325 J
ΔU = 111.325 J
Rounded to three significant figures, the change in internal energy is 111 J.
Answer:
A producer is a plant or fungi but it mainly is a organism that produces food for a primary consumer
Explanation:
Answer:
The reaction will be spontaneous
Explanation:
To determine if the reaction will be spontaneous or not at this temperature, we need to calculate the Gibbs's energy using the following formula:
<u>If the Gibbs's energy is negative, the reaction will be spontaneous, but if it's positive it will not.</u>
Calculating the 
:
Now, other factor we need to determine is the sign of the S variation. When talking about gases, the more moles you have in your system the more enthropic it is.
In this reaction you go from 7 moles to 8 moles of gas, so you can say that you are going from one enthropy to another higher than the first one. This results in: ![\Delta S>0[/tex}Back to this expression: [tex]\Delta G= -1267 - 473 K* \Delta S](https://tex.z-dn.net/?f=%5CDelta%20S%3E0%5B%2Ftex%7D%3C%2Fp%3E%3Cp%3EBack%20to%20this%20expression%3A%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%5CDelta%20G%3D%20-1267%20-%20473%20K%2A%20%5CDelta%20S%20)
If the variation of S is positive, the Gibbs's energy will be negative always and the reaction will be spontaneous.
