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Mandarinka [93]
3 years ago
10

Dicarbon monoxide, C2O, is found in dust clouds in space. Analysis of it shows that the sequence of atoms in this molecule is C–

C–O. All bonds are double bonds and there are no unpaired electrons. How many lone pairs of electrons are present in a molecule of C2O?
Chemistry
2 answers:
lorasvet [3.4K]3 years ago
8 0

Hello there,


Ione pairs of electrons that are present in a molecule of C2O are...

4

Each Oxygen forms two bonds with Carbon


Hope I Helped!

-Char

katovenus [111]3 years ago
5 0

Answer:

Three

Explanation:

Each C atom supplies four valence electrons and each O atom supplies six, for a total of 14 valence electrons.

If there are two double bonds (eight bonding electrons), there must be six nonbonding electrons (i.e., three lone pairs).

The Lewis structure of C₂O is :C=C=Ö:

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Answer:

With less energy at higher trophic levels, there are usually fewer organisms as well

Explanation: Organisms tend to be larger in size at higher trophic levels, but their smaller numbers result in less biomass. Biomass is the total mass of organisms at a trophic level.

4 0
3 years ago
How many moles of CO are present in 35.88 L of the gas?
Pepsi [2]

Answer:

1.602 moles CO

Explanation:

To convert from liters to moles, divide by 22.4:

35.88 L / 22.4 = 1.602 moles CO

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Use the Earth's Energy Budget diagram to answer the question. Based on the diagram, less solar energy that reaches Earth is ____
Ivan
<span>absorbed, radiated
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3 years ago
How many protons are in an atom of strontium?
Stells [14]

Answer:

38

Explanation:

Symbol: Sr

Atomic mass: 87.62 u

Electrons per shell: 2,8,18,8,2

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7 0
3 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
Katyanochek1 [597]

Answer:

a=64.7mg

Explanation:

Hello,

In this case, we need to remember that for the required time for a radioactive nuclide as radium-226 to decrease to one half its initial amount we are talking about its half-life. Furthermore, the amount of remaining radioactive material as a function of the half-lives is computed as follows:

a=a_0(\frac{1}{2} )^{\frac{t}{t_{1/2}} }

Therefore, for an initial amount of 100 mg with a half-life of 1590 years, after 1000 years, we have:

a=100mg(\frac{1}{2} )^{\frac{1000years}{1590years} }\\\\a=64.7mg

Best regards.

4 0
3 years ago
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