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Mandarinka [93]
3 years ago
10

Dicarbon monoxide, C2O, is found in dust clouds in space. Analysis of it shows that the sequence of atoms in this molecule is C–

C–O. All bonds are double bonds and there are no unpaired electrons. How many lone pairs of electrons are present in a molecule of C2O?
Chemistry
2 answers:
lorasvet [3.4K]3 years ago
8 0

Hello there,


Ione pairs of electrons that are present in a molecule of C2O are...

4

Each Oxygen forms two bonds with Carbon


Hope I Helped!

-Char

katovenus [111]3 years ago
5 0

Answer:

Three

Explanation:

Each C atom supplies four valence electrons and each O atom supplies six, for a total of 14 valence electrons.

If there are two double bonds (eight bonding electrons), there must be six nonbonding electrons (i.e., three lone pairs).

The Lewis structure of C₂O is :C=C=Ö:

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An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

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Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
Lera25 [3.4K]

The allowable combination for the atomic orbital is n=4, l=2, m_{l}=2.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 4, l can four values: 0, 1, 2, and 3. To be consistent with m_{l}=+2the l value must be higher than 1. There are two l values that are consistent with n and m_{l} values:  l= 2 or 3

Therefore, the allowable condition is n=4, l=2, m_{l}=2

To know more about quantum numbers, visit: brainly.com/question/16979660

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3 0
2 years ago
After 252 days, a 12.0-g sample of the radioisotope scandium-46 contains only 1.5 g of the isotope. what is the half-life of sca
arsen [322]
The half life of a scandium-46 is 84 days. The scandium-46<span> is used in oil refining as a tracer to monitor the oil movement and it emits </span><span>extremely high energetic gamma/beta radiation. So the half-life of the radioisotope scandium-46 is 84 days. The </span>Scandium 46 created by neutron activation, is a synthetic isotope of Scandium.
6 0
3 years ago
Write the ionic formula for mercury (II) sulfide.
skad [1K]
The formula is HgS

Hope this helps :D
5 0
3 years ago
In a piston, the volume was noticed to be 2.50 liters at 25°C. If the temperature rose to 55°C, what is the new volume?
GrogVix [38]

Answer:

The new volume is 2.75L

Explanation:

This is another case of Charles Gay Lussac law, where the volume varies directly proportional to T°, if the pressure keeps on constant.

V₁ / T₁  =  V₂ / T₂

25°C + 273 = 298K

55°C + 273 = 328K

2.5L / 298K = V₂ / 328K

(2.5L / 298K) . 328K = V₂

2.75L = V₂

8 0
4 years ago
Read 2 more answers
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