1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
devlian [24]
3 years ago
7

Hello! for titration method , why is alkali used instead of bases?

Chemistry
1 answer:
34kurt3 years ago
6 0

Your question has been heard loud and clear.

Uhm , Alkalis are just bases who react with water. In titration we use water also , so we need bases that react with water , and such bases are alkalis.

Alkalis are a type of bases.

Thank you

You might be interested in
All radioactive nuclides undergo what
kotykmax [81]
They undergo nuclear fission.
6 0
2 years ago
The typical atmospheric pressure on top of Pikes Peak, Colorado (14109 ft. ) is 656.2 torr. Convert the pressure to :
myrzilka [38]
21.5010667479427 I goth this asnswer cause I divided I think that's how u do it
5 0
3 years ago
Помогите пожалуйста или с первым вопросом или со вторым. Буду очень благодарна, т.к. это мой зачет... :С
Bess [88]
Hsiaqoanwbwiso iDisks
5 0
3 years ago
Which is a major environmental concern for our oceans?
padilas [110]
Plastic pollution is the correct answer
3 0
2 years ago
Read 2 more answers
A 10.5 mL sample of vinegar, containing acetic acid, was titrated using 0.460 M NaOH solution. The titration required 19.13 mL o
laila [671]

Explanation:

Step 1:

A good first step for a problem like this is to write down the chemical formula and balance it.

It appears here that we have 10.5 mL of vinegar, which IS acetic acid, and 19.13 mL of 0.460 M NaOH. That will give us the following balanced chemical equation:

CH3COOH + NaOH ------> NaCH3COO + H2O

All of the constituents come out to a value of 1, conveniently.

Step 2:

Since all of our stoichiometric coefficients are one, we can use a shortcut to answer this equation. I don't know if it has a name, but I just call it the titration formula. It goes something like this:

M1 * V1 = M2 * V2

M stands for Molarity and V stands for volume. 1 and 2 being the before the reaction and after the reaction.

So, our M1 for this is going to be what the question says was used for this titration. That's 0.460M NaOH.

Our V1 is going to be the initial volume of the sample, which was 10.5 mL

Our V2 is going to be 19.13, which is the volume when we're finished.

It's clear that we don't know M2, so let's find it.

Keep in mind that it's easier to convert to liters pretty much always, so I've done that by dividing the mL values each by 1000.

Using some algebra, we can see that we now have:

0.460 M * 0.0105 L = x M * 0.01913 L

Which goes to:

\frac{0.00483mol}{0.01913L} = 0.252 M

<h3>So our M2, the molar concentration of acetic acid in this vinegar, is equal to 0.252 M. </h3>
3 0
3 years ago
Other questions:
  • After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2 is
    12·1 answer
  • A diatom is a(n) _______ because it has _______.
    8·1 answer
  • 8. Which of the following is a method of purifying water?
    11·2 answers
  • What Is the name of the force that holds together the sub Tomic particles of the nuclear?
    10·1 answer
  • Dichloromethane contains strong carbon - hydrogen and carbon- chlorine bonds. Despite the presence of these strong bonds. dichlo
    11·1 answer
  • ¿Puede ocurrir una reacción química sin generar cambios visibles?
    15·1 answer
  • Baking soda (NaHCO3, 84.0 g/mol) requires acids from other ingredients to generate the carbon dioxide needed to make bread rise.
    5·1 answer
  • Pls answer how many neutrons, protons, and electrons there are. I will give points, thanks, 5 stars, and brainliest if you answe
    8·1 answer
  • HELP ME PLEASE <br> T-T thanks
    15·1 answer
  • A lake has a surface area of 16.0 square miles and an average depth of 49.0 feet.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!