D. Small geographic range
<span>There are a number of ways
to express concentration of a solution. This includes molarity. Molarity is
expressed as the number of moles of solute per volume of the solution.
Calculations are as follows:
Molarity of NO3 ion = 32.0 g Mg(NO3)2 ( 1 mol / 148.3 g ) ( 2 mol NO3 / 1 mol Mg(NO3)2) / .425 L
MOlarity of NO3 ion = 1.02 M </span><span>
</span>
Answer:
C 108
Explanation:
1 It was found that 4n atoms of metal x
weigh 501.6 g. The relative atomic mass
of X is 209. If n atoms of another metal,
Y, weigh 65.00 g, what is the relative
atomic mass of metal Y?
A 27 B 52 C 108 D 137
if 4n atoms of x weigh 501.6 gm, the n atoms weigh 501.6/4 = 125.4 gms
since the atomic mass is 209, then 6.022 X10^23 atom weigh 209
the ratio of 125.4 to 209 is
125.4/Y =0.6
therefor n is the number of atom in 0.6 moles
if metal Y has the same, number of atoms "n" and weighs 65 gm
then then the relative atomic mass is
65/0.6 =108
so the answer is
C 108
I believe <span>Na2SO3 is the solution to the problem.</span>
