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LiRa [457]
4 years ago
10

A cart moves toward a motion sensor on a track in three different ways: speeding up with constant speed slowing to a stop and tu

rning around to speed up in the opposite direction For each of these cases, what is the sign of the velocity and what is the sign of the acceleration at the beginning of the trip and at the end of the trip?
Physics
1 answer:
devlian [24]4 years ago
4 0

Answer:

Acceleration of the cart in the beginning is positive

Speed is positive when speeding up and slowing down.

Speed is zero when the cart stops.

Speed is negative when the cart speeds up in opposite direction.

Acceleration is negative when speeding up in opposite direction from rest.

Explanation:

When the cart is speeding up then its speed is increasing with time hence its acceleration is having a positive  value.

  • On speeding up the velocity is positive.
  • On gradually decreasing the speed and coming to a stop the velocity is still positive with continuously decreasing magnitude until it reaches zero when the cart stops.
  • When the cart speeds up in the opposite direction then the velocity of the cart becomes negative from zero and continuously increases in the negative value over a span of time hence its acceleration is also negative.

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3 years ago
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A student uses a microwave oven to heat a meal. The wavelength of the radiation is 8.97 cm. What is the energy of one photon of
krek1111 [17]

Answer:

The energy of one photon is 2.21x10⁻²⁴ J. Multiplied by 10²⁵ is 22.10 J.

         

Explanation:  

The energy (E) of a photon is:

E = h\frac{c}{\lambda}

Where:

h: is the Planck's constant = 6.62x10⁻³⁴ J.s

λ: is the wavelength of the radiation = 8.97 cm

c: is the speed of light = 3.00x10⁸ m/s

E = h\frac{c}{\lambda} = 6.62 \cdot 10^{-34} J.s\frac{3.00\cdot 10^{8} m/s}{8.97 \cdot 10^{-2} m} = 2.21 \cdot 10^{-24} J

Hence, the energy of one photon is 2.21x10⁻²⁴ J.

Now, if we multiply the answer by 10²⁵ we have:

E = 2.21 \cdot 10^{-24} J \cdot 10^{25} = 22.10 J

I hope it helps you!

8 0
3 years ago
What are the wavelengths of electromagnetic wave in free space that have the following frequencies?
Ne4ueva [31]

Explanation:

Given that,

(a) Frequency, f_1=4\times 10^{19}\ Hz

All electromagnetic wave moves with the speed of light. It is given by :

c=f\lambda

\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{4\times 10^{19}}\\\\\lambda_1=7.5\times 10^{-12}

(b) Frequency, f_2=5.5\times 10^{1=9}\ Hz

All electromagnetic wave moves with the speed of light. It is given by :

c=f\lambda

\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{5.5\times 10^{9}}\\\\\lambda_2=0.054\ m

Hence, this is the required solution.

7 0
3 years ago
A car traveled 176 miles on 6.4 gallons of fuel the car averaged how many miles per gallon
earnstyle [38]
It would be 27.5 miles per gallon
3 0
3 years ago
A very long, solid insulating cylinder has radius R; bored along its entire length is a cylindrical hole with radius a. The axis
lawyer [7]

Answer:

The value of the electric field is E_{net} = \dfrac{r \textbf{b}}{2\epsilon_{0}}

Explanation:

We know that the electric field inside a solid cylinder at a distance \textbf{r} from the centre is given by

E = \dfrac{\rho \textbf{r}}{2 \epsilon_{0}}

Let's consider the cross-section of the cylinder as shown in the figure. Let `O' be the centre of the long solid insulating cylinder having radius 'R'. Also consider that O' be the cetre of the hole of radius 'a' situated at a distance 'b' from 'O'. Given, the volume charge density of the material is 'r'. So, the volume charge density inside the hole will be '-r'. Let's consider 'P' be any arbitrary point inside the hole situated at a distance 's' from O'.

So, the electric field 'E_{O}' due to the long cylinder at point 'P' is given by

E_{O} = \dfrac{r \textbf{c}}{2 \epsilon_{0}}

and the electric field 'E_{O'}'due to the hole at point 'P' is given by

E_{O'} = \dfrac{\rho \textbf{s}}{2 \epsilon_{0}}

So the net electric field (E_{net}) inside the hole is given by

E_{net} = E_{O} - E_{O'} = \dfrac{r}{2\epsilon_{0}}(\textbf{c - s}) = \dfrac{r \textbf{b}}{2\epsilon_{0}}

5 0
4 years ago
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