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Rashid [163]
3 years ago
10

What are the wavelengths of electromagnetic wave in free space that have the following frequencies?

Physics
1 answer:
Ne4ueva [31]3 years ago
7 0

Explanation:

Given that,

(a) Frequency, f_1=4\times 10^{19}\ Hz

All electromagnetic wave moves with the speed of light. It is given by :

c=f\lambda

\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{4\times 10^{19}}\\\\\lambda_1=7.5\times 10^{-12}

(b) Frequency, f_2=5.5\times 10^{1=9}\ Hz

All electromagnetic wave moves with the speed of light. It is given by :

c=f\lambda

\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{5.5\times 10^{9}}\\\\\lambda_2=0.054\ m

Hence, this is the required solution.

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A ball hangs on the end of a string that is connected to the ceiling so that it swings like a pendulum. You pull the ball up so
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Answer:

When extra energy is added

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When the ball is released from rest and swings back towards your face, it will only pass closer to the end of the nose as per the initial conditions. However, when extra energy is added to the ball, it strikes the nose since its velocity and heights are increased. Therefore, the only condition under which the ball hits your nose is when extra energy is added to the system.

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The strength of an electromagnet CANNOT be increased by?
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reversing the current

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If you catch the ruler 4.9 cm from the lower end, what is your reaction time?
Luba_88 [7]

Answer:

0.10s

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Identify the two functional groups that react to form polyester.
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3 0
3 years ago
A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the f
professor190 [17]
When the iron and the water reach thermal equilibrium, they have same temperature, T=58.5^{\circ}C.
We can consider this as an isolated system, so the heat released by the water is equal to the heat absorbed by the iron.

The hear released by the water is:
Q_w =m_w C_{sw} \Delta T_w
where m_w is the water mass, C_{sw}=4.186 J/(g^{\circ}C) is the specific heat of the water, and \Delta T_w = 63.6^{\circ}-58.5^{\circ}=5.1^{\circ}C is the variation of temperature of the water.

Similarly, the heat absorbed by the iron is:
Q_i = m_i C_{si} \Delta T_i
where m_i = 33.0 g is the iron mass, C_{si}=0.444 J/(g^{\circ}C) is the iron specific heat, and \Delta T_i = 58.5^{\circ}-22.7^{\circ}=35.8^{\circ}C is the variation of temperature of the iron.

Writing Q_w=Q_i and replacing the numbers, we can solve to find mw, the mass of the water:
m_w= \frac{m_i C_{si} \Delta T_i}{C_{sw} \Delta T_w} =24.6 g
4 0
3 years ago
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