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nadezda [96]
2 years ago
9

Which statement is a true catalyst in a reaction

Physics
1 answer:
mote1985 [20]2 years ago
4 0

Answer:

it alters the rate of chemical reaction

hope it is useful

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An ant walks 2\,\text m2m2, start text, m, end text to the right and then climbs 1 \,\text m1m1, start text, m, end text up a wa
NNADVOKAT [17]

Answer:

26.56°

Explanation:

given,

horizontal distance travel by the ant = 2 m

vertical distance travel by the ant = 1 m

angle of the ant above the initial point = ?

using trigonometric function

tan \theta = \dfrac{h}{x}

θ is the angle of the ant form initial position

h is the height on the wall

x is the horizontal distance covered by the ant

tan \theta = \dfrac{1}{2}

\theta =tan^{-1}(0.5)

\theta =26.56^0

hence, the angle made by the ant from the initial position is equal to 26.56°

3 0
3 years ago
What is meant by a charge carrier hole in a semiconductor? Can it be created in a conductor? ​
lara [203]

Answer:

The materials used to make electronic components like transistor and integrated, circuit behave as if effective particles known as electron through them, causing electrical properties

6 0
3 years ago
What is the least number of forces required to stretch a spring?
Solnce55 [7]

Answer:

The least number of forces required to stretch a spring is one.

Explanation:

Let suppose that spring is ideal, that is, that effects from its mass can be neglected since it is insignificant in comparison with external forces. In addition, let the spring have a linear behavior, meaning that net external longitudinal force exerted on spring is directly proportional to defomation. (Hooke's Law) That is:

F \propto x (1)

F = k\cdot x (2)

Where:

F - Net external force, measured in newtons.

k - Spring constant, measured in newtons per meter.

x - Deformation of spring, measured in meters.

Hence, the least number of forces required to stretch a spring is one.

7 0
3 years ago
A piano wire with mass 3.00 g and length 80.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and ampli
lys-0071 [83]

Answer:

(a) P_{avg} = 0.22 W

(b) P_{avg,2} = 0.056 W

Explanation:

given information:

the mass of piano wire, m = 3.00 g = 0.003 kg

tension, F = 25 N

length, l = 80 cm = 0.8 m

frequency, f = 120 Hz

amplitude, A = 1.6 mm = 0.0016 m

(a) the average power carried by the wave, P_{avg}

P_{avg} = \frac{1}{2}(√μF)ω²A²

where,

ω = 2πf = 2π120 = 754s^{-1}

μ = \frac{m}{l}

  = \frac{0.003}{0.8}

  = 0.00375 kg/m

thus,

P_{avg} = \frac{1}{2}(√(0.00375)(25))(754)²(0.0016)²

P_{avg} = 0.22 W

(b) What happens to the average power if the wave amplitude is halved.

based on the equation above, we know that the average power is proportional to the square amplitude. therefore

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{A_{2} ^{2} } }

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{(0.5A_{1} )^{2} } }

P_{avg,2} = \frac{0.22}{4}

P_{avg,2} = 0.056 W

4 0
3 years ago
Water in the air combines with
valentina_108 [34]

Answer:b

Explanation:

6 0
3 years ago
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