Answer:
Tension of 132N
Explanation:
We need to apply Summatory of Force to find the tension in the hand.
We define te tensión in the hand as
and the Tension in fence post as
, then
![\sum F = 24(9.8)](https://tex.z-dn.net/?f=%5Csum%20F%20%3D%2024%289.8%29)
![F_1 + F_2= 24(9.8)](https://tex.z-dn.net/?f=F_1%20%2B%20F_2%3D%2024%289.8%29)
We apply summatory of moments then
![F_2*1.25 = F_1*1.6](https://tex.z-dn.net/?f=F_2%2A1.25%20%3D%20F_1%2A1.6)
Where the Force 2 is 1.25m from the center of summatory,
We can note that,
![1.6 m - 0.35m=1.25m](https://tex.z-dn.net/?f=1.6%20m%20-%200.35m%3D1.25m)
We have two equation and two incognites, then replacing (1) in (2)
![1.6(235.2 -F_2) = 1.25F_2](https://tex.z-dn.net/?f=1.6%28235.2%20-F_2%29%20%3D%201.25F_2)
![376.32 = F2(1.6+1.25)](https://tex.z-dn.net/?f=376.32%20%3D%20F2%281.6%2B1.25%29)
![F_2= \frac{376.32}{2.85}](https://tex.z-dn.net/?f=F_2%3D%20%5Cfrac%7B376.32%7D%7B2.85%7D)
![F_2 =132 N](https://tex.z-dn.net/?f=F_2%20%3D132%20N)
Answer:
s = 23.72 m
v = 21.56 m/s²
Explanation:
given
time to reach the ground (t) = 2.2 second
we know that
a) s = u t + 0.5 g t²
u = 0 m/s
g = 9.8 m/s²
s = 0 + 0.5 × 9.8 × 2.2²
s = 23.72 m
b) impact velocity
v = √(2gh)
v = √(2× 9.8 × 23.72)
v = √464.912
v = 21.56 m/s²
Answer: heat
Insulation Traps Heat. Keeping the cold air out
Explanation:
Answer:
Velocity = 4.33[m/s]
Explanation:
The total energy or mechanical energy is the sum of the potential energy plus the kinetic energy, as it is known the velocity and the height, we can determine the total energy.
![E_{M}=E_{p} + E_{k} \\E_{p} = potential energy [J]\\E_{k} = kinetic energy [J]\\where:\\E_{p} =m*g*h\\E_{p} = 4*9.81*0.5=19.62[J]\\E_{k}=\frac{1}{2} *m*v^{2} \\E_{k}=\frac{1}{2} *4*(3)^{2} \\E_{k}=18[J]\\Therefore\\E_{M} =18+19.62\\E_{M}=37.62[J]](https://tex.z-dn.net/?f=E_%7BM%7D%3DE_%7Bp%7D%20%20%2B%20E_%7Bk%7D%20%5C%5CE_%7Bp%7D%20%3D%20potential%20energy%20%5BJ%5D%5C%5CE_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5D%5C%5Cwhere%3A%5C%5CE_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5CE_%7Bp%7D%20%3D%204%2A9.81%2A0.5%3D19.62%5BJ%5D%5C%5CE_%7Bk%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%20%20%5C%5CE_%7Bk%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%2A4%2A%283%29%5E%7B2%7D%20%5C%5CE_%7Bk%7D%3D18%5BJ%5D%5C%5CTherefore%5C%5CE_%7BM%7D%20%3D18%2B19.62%5C%5CE_%7BM%7D%3D37.62%5BJ%5D)
All this energy will become kinetic energy and we can find the velocity.
![37.62=\frac{1}{2} *m*v^{2} \\v=\sqrt{\frac{37.62*2}{4} } \\v=4.33[m/s]](https://tex.z-dn.net/?f=37.62%3D%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B37.62%2A2%7D%7B4%7D%20%7D%20%5C%5Cv%3D4.33%5Bm%2Fs%5D)