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3 years ago

Jane has a mass of 40 kg. She pushes on a 50 kg rock with a force of 100 N. What force does the rock exert on Jane?

1 answer:

6 0

I know something that a lot of people know but they get in trouble when they try to use it. I got it a long time ago from my old school buddy Ike Newton. I'll tell it to you, but you have to keep it to yourself, don't spread it around, and don't tell a lot of people where you got it.

Here it is:

For every action, there is a reaction that is EQUAL and opposite.

That means that if Jane pushes on the rock with 100 Newtons of force,

then The rock pushes on Jane with 100 Newtons of force.

It doesn't matter how much Jane's mass is, it doesn't matter what the mass of the rock is, and it doesn't even matter whether Jane is moving, or the rock is moving, or both of them are moving. If there's an action, then you can bet yer britches that there's a RE-action, and the RE-action is EQUAL and OPPOSITE to the action.

Why is this so hard ?

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A yellow and green car traveled 400 miles to Dayton, OH. The green car made the trip in 10 hours. The yellow arrived in 8 hours.

elixir [45]

Answer: C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

Explanation:

The speed of each car is defined as:

$v=\frac{d}{t}$

where d is the distance traveled by the car and t is the time taken.

For the yellow car, d=400 mi and t=8 h, so its speed is

$v=\frac{400 mi}{8 h}=50 mph$

For the green car, d=400 mi and t=10 h, so its speed is

$v=\frac{400 mi}{10 h}=40 mph$

So, the correct choice is

C)The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.

4 0

4 years ago

Read 2 more answers

a certain projetor uses a concave mirror for projecting an object's image on a screen .it produces on image that is 4 times bigg

IrinaK [193]

Answer:

f = 1 m

Explanation:

The magnification of the lens is given by the formula:

$M = \frac{q}{p}$

where,

M = Magnification = 4

q = image distance = 5 m

p = object distance = ?

Therefore,

$4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m$

Now using thin lens formula:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\$

f = 1 m

6 0

3 years ago

26. A transformer increases or decreases

uysha [10]

Answer:

Explanation:

Single-phase transformers can operate to either increasing or decreasing the voltage applied to the primary winding. When a transformer is used to “increase” the voltage on the secondary winding with respect to the primary, it is called a Step-up transformer

7 0

3 years ago

Which characteristics of an area could best identify the type of biome it is

jeka94

Answer: average annual rainfall, average annual temperatures, types of plants and animals native to the area

Explanation: the best way you can identify a biome is by telling which animal or species are native to the certain area

6 0

3 years ago

A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.8 m/s rel

Svetach [21]

I'm assuming the question is what is the robin's speed relative to to the ground...

Create an equation that describes its relative motion.

rVg = rVa + aVg

Substitute values.

rVg = 12 m/s [N] + 6.8 m/s [E]

Use vector addition.

| rVg | = √ | rVa |² + | aVg |²

| rVg | = √ 144 m²/s² + 46.24 m²/s²

| rVg | = √ 190.24 m²/s²

| rVg | = 13.78 m/s

Find direction.

tanФ = aVg / rVa

tanФ = 6.8 m/s / 12 m/s

Ф = 29°

Therefore, the velocity of the robin relative to the ground is 14 m/s [N29°E]

4 0

3 years ago