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3 years ago

Jane has a mass of 40 kg. She pushes on a 50 kg rock with a force of 100 N. What force does the rock exert on Jane?

1 answer:

6 0

I know something that a lot of people know but they get in trouble when they try to use it. I got it a long time ago from my old school buddy Ike Newton. I'll tell it to you, but you have to keep it to yourself, don't spread it around, and don't tell a lot of people where you got it.

Here it is:

For every action, there is a reaction that is EQUAL and opposite.

That means that if Jane pushes on the rock with 100 Newtons of force,

then The rock pushes on Jane with 100 Newtons of force.

It doesn't matter how much Jane's mass is, it doesn't matter what the mass of the rock is, and it doesn't even matter whether Jane is moving, or the rock is moving, or both of them are moving. If there's an action, then you can bet yer britches that there's a RE-action, and the RE-action is EQUAL and OPPOSITE to the action.

Why is this so hard ?

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3 years ago

A diet rich in high-density lipoproteins (HDLs) can help cleanse and open arteries that are clogged with plaque.

docker41 [41]

Correct answer choice is :

A) True

Explanation:

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3 years ago

Read 2 more answers

A florescent light tube usually contains what?

Nady [450]

Answer:

mercury vapour

Explanation:

it contains many other gases and it contains mercury vapour

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4 years ago

These problems involve Impulse-Mometum theorem, and the Work-Kinetic Energy theorem. Both theorems are combinations of Newton's

ira [324]

a) The time needed to stop the car is 82.5 s

b) The final speed of the bullet is 23,625 m/s

Explanation:

We can solve this part of the problem by using the impulse-momentum theorem, which states that:

"The impulse exerted on an object (the product between force applied and time interval) is equal to the change in momentum of the object"

Mathematically:

$F\Delta t = m\Delta v$

where

F is the force applied

$\Delta t$ is the time interval

m is the mass of the object

$\Delta v$ is the change in velocity

For the train car in this problem, we have

m = 16000 kg is the mass

F = -1900 N is the force applied (with negative sign, since it is applied in the direction opposite to the direction of motion, in order to stop the train)

$\Delta v = 0 -9.8 m/s = -9.8 m/s$ is the change in velocity of the car