Which layer would a person drilling a well most likely reach after drilling through the unsaturated zone?

Physics

2 answers:

Vlada [557]4 years ago

7 0

Answer:

the water table

Explanation:

Flauer [41]4 years ago

6 0

An aquifer is the most expected feature that is likely to be reach after drilling through the unsaturated zone. Aquifer has tendency to transform ground water to the surface through voids. The depth of aquifer varies.

You might be interested in

A 30.0-kg packing case is initially at rest on the floor of a1500-kg pickup truck. The coefficient of static friction betweenthe

777dan777 [17]

Answer:

Explanation:

a ) maximum friction possible

= .3 x 30 x 9.8

= 88.2 N

It is friction force which creates acceleration in 30 kg packing case.

Friction force F

F = ma

= 30 x 2.51

= 75.3 N

It will be in north direction , the direction of acceleration.

b ) F = ma

= 30 x 3.63

= 108.9 N

But maximum friction force is 75.3 N , so load will start slipping northward. so friction force will be acting southward.

Friction force = .2 x 30 x 9.8 ( coefficient of kinetic friction applies )

= 58.8 N

towards south .

5 0

3 years ago

Kwanzaa farts apple juice

8_murik_8 [283]

Answer:

well

Explanation:

7 0

3 years ago

Astronomers observe a quasar and measure its spectrum. A particular spectral line has a value of 279.8 nm when measured using a

Arada [10]

Answer:

$v=-80.5*10^{6}m/s$

Explanation:

For this particular problem, we are going to use the non-relativistic Doppler effect which, is the change in frequency of a wave concerning an observer who's moving relative to the wave source. The shifted wavelength is:

$\lambda_{shifted}=\lambda_{0}\left(1+\dfrac{v}{c_{0}}\right)$ ,

where $\lambda_{0}$ is the wavelenght as it comes from the source, $v$ is the velocity of the source (the quasar) and, $c_{0}$ is the velocity of the wave. In this case, the velocity of the wave is the speed of light, $c_{0}=c=3*10^{8}\ m/s$ .