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3 years ago

Which layer would a person drilling a well most likely reach after drilling through the unsaturated zone?

Physics

2 answers:

Vlada [557]3 years ago

7 0

Answer:

the water table

Explanation:

Flauer [41]3 years ago

6 0

An aquifer is the most expected feature that is likely to be reach after drilling through the unsaturated zone. Aquifer has tendency to transform ground water to the surface through voids. The depth of aquifer varies.

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Lab report 1.04 hypothesis

Zanzabum

Answer:a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Hope This helps!!

5 0

3 years ago

Briefly describe the difference between the behaviorist, nativist, and interactionist language acquisition theories.

Over [174]

Answer:

Described below

Explanation:

- The behaviorist theories: This theory is of the claim that language is learned through the means of reinforcement and imitation. This means that little children can mimic the language of individuals around them and also receive reinforcement to correct the formation of their words. Thereafter, words not reinforced will eventually no longer be in use.

- The nativist theories: This theory is of the claim that individuals possess an innate process which is used in language learning and is widely known as "language acquisition device" (LAD). This device is used to assist in helping them automatically learn languages.

-The interactionist theories: This theory is of the claim that innate processes which is also referred to as genetic predispositions and learning experiences from the environment both help in language development.

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3 years ago

Why is the sky blue and doesn't change color

Softa [21]

The statement is <u>false</u> because the sky <u>can change </u>colors during sunsets, sun rises, etc. The sky is not always blue.

7 0

2 years ago

I will be so thankful if u answer correctly!!

polet [3.4K]

Explanation:

The acceleration due to gravity on earth $g_{E}$ is given by

$g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}$

where $G$ = universal gravitational constant

$\:\:\:\:\:\:\:\:\:\:\:\:M_{R}$ = mass of the earth

$\:\:\:\:\:\:\:\:\:\:\:\:R_{E}$ = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity $g_{K}$ is

$g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}$

$\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}$

$\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}$

$g_{K} = (\dfrac{2}{9})\:g_{E}$

If we multiply both sides by Superman's mass, we get his weights on both planets:

$mg_{K} = (\dfrac{2}{9})\:(mg_{E})$

$W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N$

3 0

2 years ago

Three identical stars of mass M form an equilateral triangle that rotates around the triangle’s center as the stars move in a co

zheka24 [161]

Answer:

$v=\sqrt{\dfrac{2GM}{L}}$

Explanation:

M = Mass of planets

R = Radius of circle

v = Velocity

$\theta$ = Angle

The circle is inside the triangle

$cos\theta=\dfrac{\dfrac{L}{2}}{R}\\\Rightarrow R=\dfrac{L}{2cos\theta}$

The centripetal acceleration

$\dfrac{Mv^2}{R}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow \dfrac{Mv^2}{\dfrac{L}{2cos\theta}}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow \dfrac{Mv^22cos\theta}{L}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow v^2=\dfrac{2GM}{L}\\\Rightarrow v=\sqrt{\dfrac{2GM}{L}}$

The speed of the stars is $v=\sqrt{\dfrac{2GM}{L}}$

5 0

3 years ago