Answer:
1) T = 649.86 s, 2) L₀ = L_f, 
= 4.8
Explanation:
1) As the system of the two bodies is isolated, its angular momentum is conserved
initial instant. r₀ = 155 m, T₀= 385.3 s
L₀ = I₀ w₀
final instant. r = 119.35 m
L_f = I w
L₀ = L_f
I₀ w₀ = I w
w = 
let's consider each object as punctual
I = m r²
at angle velocity and period are related
w = 2pi / T
we substitute
T = 
let's calculate
T = 
T = 649.86 s
2) The angular momentum is conserved because the system is isolated.
Let's look for kinetic energy
K_total = 2 K = 2 (½ I w²)
K_total = I 4π² / T²
K_total = 2m r² 4 π² / T²
for r = 155 m
K₀ = 8π² m r₀² / T₀²
for r = 119.35 m
K_f = 8π² m r² / T²
the relationship is
= 4.8
The correct options are:
<span>1) The force between two charged objects increases as the charge of either one of the objects is increased.
4) The force between two charged objects increases as the objects are placed closer together.
In fact, the electrostatic force is given by Coulomb's law:
</span>
<span>where k is the Coulomb's constant, q1 and q2 are the two charges, r is the separation between the two charges. As we can see from the equation, if one of the charges (q1 or q2) is increased, than the force increases as well (so statement 1) is correct), and if the two objects are placed closer together (r is decreased), the force F increases as well (so statement 4 is correct as well)</span>
light bounces off a boundary and light direction is determined using the lawof reflection
I hope it helped
4m/s is the answer you are looking for
