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Fudgin [204]
4 years ago
9

A system consists of N very weakly interacting particles at a temperature T sufficiently high so that classical statistical mech

anics is applicable. Each particle has a mass m and is free to perform one-dimensional oscillations about its equilibrium position. Calculate the heat capacity of this system of particles at this temperature in each of the following cases:

Engineering
1 answer:
algol [13]4 years ago
7 0

Answer:

the restoring force is = 3/4NKT

Explanation:

check the attached files for answer.

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A converging nozzle has an exit area of 0.001 m2. Air enters the nozzle with negligible velocity at a pressure of 1 MPa and a te
Artyom0805 [142]

Explanation:

a converging nozzle has an exit area of 0.001 m2. Air enters the nozzle with negligible velocity at a pressure of 1 MPa and a temperature of 360 K. For isentropic flow of an ideal gas with k = 1.4 and the gas constant R = Ru/MW = 287 J/kg-K, determine the mass flow rate in kg/s and the exit Mach number for back pressures

100% (3 ratings)

A_2 = 0.001 m^2 P_1 = 1 MPa, T_1 = 360 k P_2 = 500 kpa p^gamma - 1/gamma proportional T (1000/500)^1.4 - 1/1.4 = (360/T_2) 2^4/14 = 360/T_2 T_2

3 0
3 years ago
Provide three examples of things engineers can implement when designing environmentally sustainable projects.
Dafna1 [17]
Water supply.
Food production.
Housing and shelter.
Sanitation and waste management.
Energy development.
Transportation.
6 0
3 years ago
Read 2 more answers
A sample of cast iron with .35 wt%C is slow cooled from 1500C to room temperature. What is the fraction of proeutectoid Cementit
Marizza181 [45]

Answer:

So the fraction of proeutectoid cementite is 44.3%

Explanation:

Given that

cast iron with 0.35 % wtC and we have to find out fraction of proeutectoid cementite phase when cooled from 1500 C to room temperature.

We know that

Fraction of  proeutectoid cementite phase gievn as

{w_p}'=\dfrac{{C_o}'-0.022}{0.74}

Now by putting the values

{w_p}'=\dfrac{0.35-0.022}{0.74}

{w_p}'=0.443

So the fraction of proeutectoid cementite is 44.3%

6 0
3 years ago
In Millikan's oil drop experiment, if the electricfield between the plates was of just the right magnitude, it wouldexactly bala
Vilka [71]

Answer:

The electric field to balance the weight is approximately equals to 3.49x10^5 Newton/Coulumb

Explanation:

In order to be stationary position, magnitude of the total force due to electric field should be equal to the gravitational force that is, |F_{electrostatic}| = |F_{gravitational}|

where

F_{electrostatic}=q.E

where <em>q</em> is the charge of the droplet and E is the electric field. On the other hand

F_{gravitational}=m.g=V.d.g=\frac{4}{3}.\pi.r^3.d.g

where <em>m</em>,<em>V ,d</em> and<em> r</em>  are the mass, volume, density and radius of the oil droplet respectively and <em>g </em>is the gravitational acceleration (g=9,80665 m/sn^2). By using the first equation and solving it for the electric field we can write,

q.E=\frac{4}{3}.\pi.r^3.d.g\\E=\frac{4}{3}.\pi.\frac{r^3.d.g}{q}\\E=\frac{4}{3}.\pi\frac{(1,6x10^{-4})^3.(0,85x10^{-3}).(9,81)}{1,6x10^{-19}}\\E\approx 3,49x10^{5}  (N/C)

(Note: d=0.85 x 10^-3 kg/cm^3 and the unit of electric field is Newton per coulumb (N/C))

8 0
3 years ago
In order to give a gradual increase in section modulus, frame reinforcement plates must be:Group of answer choicesrectangular.cu
Nataliya [291]

Answer:

Technician A says that when fifth wheel brackets are bolted to frame rails, the section modulus over that section of the frame is increased.

Explanation:

hope i helped

6 0
3 years ago
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