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Mashcka [7]
3 years ago
13

1) What output force (Fout) is produced if the lever arm length (rout) is 100 mm?

Engineering
2 answers:
valentina_108 [34]3 years ago
8 0
Im not sure but I need points I’m sorry
Ierofanga [76]3 years ago
6 0
The length of the arm is the main part of natur
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Polymers can be natural or synthetic. a)-True b)- false?
Olenka [21]

Answer:

TRUE

Explanation:

Polymers can be natural as well as synthetic

The polymer which are found in nature are called natural polymer tease polymer are not synthesized, they are found in nature

Example of natural polymers is cellulose, proteins etc

On the other hand synthetic polymers are not found in nature they are synthesized in market

There are many example of synthetic polymer

Example : nylon, Teflon etc  

So it is a true statement

8 0
4 years ago
A specimen has circular cross-sectional area with initial diameter d = 26 mm and a gauge length Lo = 200 mm. A force P = 127 kN
steposvetlana [31]
The ahahte ekiebecwkwlwtfe einshgeh dinzgdwbsine ensue d
4 0
3 years ago
An isolation transformer whose main purpose is to reduce voltage spikes will have a turns ratio of?
garik1379 [7]

Answer:

An isolation transformer whose main purpose is to reduce voltage spikes will have a turns ratio of 1 to 1.

This is due to the windings input and output having the same waveform and amplitude.

6 0
2 years ago
A solid cylindrical workpiece made of 304 stainless steel is 150 mm in diameter and 100 mm is high. It is reduced in height by 5
goblinko [34]

Answer:

45.3 MN

Explanation:

The forging force at the end of the stroke is given by

F = Y.π.r².[1 + (2μr/3h)]

The final height, h is given as h = 100/2

h = 50 mm

Next, we find the final radius by applying the volume constancy law

volumes before deformation = volumes after deformation

π * 75² * 2 * 100 = π * r² * 2 * 50

75² * 2 = r²

r² = 11250

r = √11250

r = 106 mm

E = In(100/50)

E = 0.69

From the graph flow, we find that Y = 1000 MPa, and thus, we apply the formula

F = Y.π.r².[1 + (2μr/3h)]

F = 1000 * 3.142 * 0.106² * [1 + (2 * 0.2 * 0.106/ 3 * 0.05)]

F = 35.3 * [1 + 0.2826]

F = 35.3 * 1.2826

F = 45.3 MN

7 0
3 years ago
Bulk wind shear is calculated by finding the vector difference between the winds at two different heights. Using the supercell w
ivanzaharov [21]

Answer:

See explaination

Explanation:

2. 0-1 km shear value: taking winds at 1000mb and 850 mb

15 kts south easterly and 50 kts southerly

Vector difference 135/15 and 180/50 will be 170/61 or southerly 61 kts

3. 0-6 km shear value: taking winds at 1000 mb and 500 mb

15 kts south easterly and 40 kts westerly

Vector difference 135/15 and 270/40 will be 281/51 kts

please see attachment

5 0
3 years ago
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