If you decrease the frequency of a vibrating object to one fourth ,its period becomes

Physics

1 answer:

shepuryov [24]3 years ago

4 0

It's period would become D

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Physical quantities expresed only by their magnitude is

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A satellite is in circular orbit around the earth. The orbit the satellite is at a height of 420 km above the earth's surface. F

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7661.06 m/s

Explanation:

R = Radius of Earth = $6.38\times 10^6\ m$

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M = Mass of Earth = $5.98\times 10^{24}\ kg$

$V=\sqrt{g{\frac{R^2}{R + h}}}\\\Rightarrow V=\sqrt{\frac{GM}{R^2}{\frac{R^2}{R + h}}}\\\Rightarrow V=\sqrt{\frac{6.674\times 10^{-11}\times 5.98\times 10^{24}}{(6.38\times 10^6)^2}{\frac{(6.38\times 10^6)^2}{6.38\times 10^6 + 420000}}}\\\Rightarrow V=7661.06\ m/s$