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Nesterboy [21]
3 years ago
8

Please help me I'll try to give brainliest if I find out how​

Chemistry
1 answer:
Vsevolod [243]3 years ago
8 0

Answer:

Acid + Oxide or Hydroxide

Many oxide, hydroxide and carbonate compounds

are insoluble in water, but do react with acid.

Acid + Oxide → Salt + Water

Acid + Hydroxide → Salt + Water

MgO (s) + HNO3 (aq) → Mg(NO3)2 (aq) + H2O (l)

CuOH (s) + HCl (aq) → CuCl (aq) + H2O (l)

Explanation:

lead compounds are the oxides: lead monoxide, PbO, in which lead is in the +2 state; lead dioxide, PbO2, in which lead is in the +4 state; and trilead tetroxide, Pb3O4. Lead monoxide exists in two modifications, litharge and massicot. Litharge, or alpha lead monoxide, is a red or reddish…

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When 1.025 g of naphthalene (c10h8) burns in a bomb calorimeter, the temperature rises from 24.25°c to 32.33°c. find δerxn for t
Goryan [66]

Answer : The \Delta E for the combustion of naphthalene is 5161.25KJ/mole

Solution : Given,

Mass of naphthalene = 1.025 g

Initial temperature = 24.25^oC

Final temperature = 32.33^oC

Specific heat capacity of calorimeter = 5.11KJ/^oC

Molar mass of naphthalene = 128 g/mole

First, we have to calculate the heat absorbed, q

Formula used :

q=c\times \Delta T=c\times (T_{final}-T_{initial})

Now put all the given values in this formula, we get

q=(5.11KJ/^oC)\times (32.33^oCT-24.25^oC)=41.29KJ

Now we have to calculate the moles of naphthalene.

Moles of C_{10}H_{8} = \frac{\text{ Mass of }C_{10}H_{8}}{\text{ Molar mass of }C_{10}H_{8}}=\frac{1.025g}{128g/mole}=0.0080moles

Now we have to calculate the \Delta E for combustion of naphthalene.

\Delta E=\frac{q}{n}

where,

q = heat absorbed

n = number of moles

Now put all the values in this formula, we get

\Delta E=\frac{41.29KJ}{0.0080moles}=5161.25KJ/mole

Therefore, the \Delta E for the combustion of naphthalene is 5161.25KJ/mole

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Calculate the moles of SO2 that contains 3.8 moles of O atoms
natima [27]
SO₂ is made from 1 S atom and 2 O atoms. 
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The stoichiometric ratio between SO₂ and O atom is 1 : 2.
Hence,
    moles of SO₂ = (moles of O atoms) / 2
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Hence, moles of SO₂ is 1.9 when there are 3.8 moles of O atoms.
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