How to take off and land, stopping considerations (stopping distance), control system capability over a large speed range and flutter, and structural integrity for the wing platform and speed range.
Answer:
True
Explanation:
True - because different classification of steel beam have different yield strength.
The moment capacity for a steel beam is given by;
M = Mn / Ωₙ
where;
M - the maximum moment acting on the beam
Ωₙ - is the Safety Factor for Elements in Bending = 1.67
Mn - nominal moment of the steel, given as

where;
Zₓ - the Plastic Section Modulus in the x or strong axis.
is the Yield Strength of the Steel (A36W, A46 W or A50W)
A36W = 36 ksi
A46 W = 46 ksi
A50W = 50 ksi
Thus, before you calculate the moment capacity for a steel beam, you have to determine the classification of beam, for the yield strength of the steel beam.
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Answer:
Explanation:
The missing diagram is attached in the image below which shows the deformation map of the Tungsten.
Given that:
Stress level 
T = 0.5 Tm

G = 160 GPa

a)
The regulating creep mechanism is dislocation driven, as we can see from the deformation mechanism.
The engineer's recommendation would not be approved because increasing grain size results in a decrease in the grain-boundary count, preferring dislocation motion. The existence of grain borders is a hindrance to dislocation motion, as the dislocation principle explicitly states. To stop the motion, we'll need a substance with finer grains, which would result in more grain borders, or a material with higher pressure. In the case of Nabarro creep, which is diffusion-driven, an engineer's recommendation would be useful.
b)
If stress level reduced to 

Cable creep is now the controlling creep mode, which entails tension-driven atom diffusion along grain borders to elongate grain along the stress axis, a process known as grain-boundary diffusion. Cable creep is more common in fine-grained materials. As a result, the engineer's advice would succeed in this case. The affinity for cable creep is reduced when the grain size is increased.
c)
From the map of creep mechanism for 
We read strain rate 
Therefore,


= 36
Therefore, 
= 
= 360 cm
Thus, the increase in length = 360 cm
Answer:
kinematic viscosity is 0.0149 ft²/s
Explanation:
given data
specific gravity S = 0.94
density ρ = 0.94 × 1000
viscosity μ = 13 Poise = 1.3 Pa-sec
we know 1 poise = 0.1 pas
to find out
kinematic viscosity
solution
we will apply here Kinematic viscosity formula that is
kinematic viscosity =
..................1
put here value in equation 1
and here ρ is density and μ is viscosity
kinematic viscosity =
kinematic viscosity = 1.382978 ×
m³/s
so kinematic viscosity is 0.0149 ft²/s