Steam in a heating system flows through tubes whose outer diameter is 5 cm and whose walls are maintained at a temperature of 19
8.06°C. Circular copper alloy fins (k =285 W/m · °C) of outer diameter 6 cm and constant thickness 1 mm are attached to the tube. The space between the fins is 3 mm, and thus there are 250 fins per meter length of the tube. Heat is transferred to the surrounding water at T= 43.06°C, with a heat transfer coefficient of 5300 W/m2 · °C. Determine the increase in heat transfer from the tube per meter of its length as a result of adding fins and fin effectiveness
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Answer:
Part 1: It would be a straight line, current will be directly proportional to the voltage.
Part 2: The current would taper off and will have negligible increase after the voltage reaches a certain value. Graph attached.
Explanation:
For the first part, voltage and current have a linear relationship as dictated by the Ohm's law.
V=I*R
where V is the voltage, I is the current, and R is the resistance. As the Voltage increase, current is bound to increase too, given that the resistance remains constant.
In the second part, resistance is not constant. As an element heats up, it consumes more current because the free sea of electrons inside are moving more rapidly, disrupting the flow of charge. So, as the voltage increase, the current does increase, but so does the resistance. Leaving less room for the current to increase. This rise in temperature is shown in the graph attached, as current tapers.
Using the knowledge of computational language in python it is possible to write a code that writes a list and defines the arrange.
<h3>Writing code in python:</h3><em>def isSorted(lyst):</em>
<em>if len(lyst) >= 0 and len(lyst) < 2:</em>
<em>return True</em>
<em>else:</em>
<em>for i in range(len(lyst)-1):</em>
<em>if lyst[i] > lyst[i+1]:</em>
<em>return False</em>
<em>return True</em>
<em>def main():</em>
<em>lyst = []</em>
<em>print(isSorted(lyst))</em>
<em>lyst = [1]</em>
<em>print(isSorted(lyst))</em>
<em>lyst = list(range(10))</em>
<em>print(isSorted(lyst))</em>
<em>lyst[9] = 3</em>
<em>print(isSorted(lyst))</em>
<em>main()</em>
See more about python at brainly.com/question/18502436
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