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Alinara [238K]
3 years ago
13

11 Notează, în caiet, trăsăturile personajelor ce se pot

Engineering
1 answer:
almond37 [142]3 years ago
6 0

Answer:a.Bianca:”Puiul de Urs loveste cu labele din fata in roata de cauciuc atarntata de-o sfoara”:Raspuns:Trasaturile puiului de urs sunt:jucaus,curios,interesat

b.Ingrijitoarea:”Doar un copil,asta esti matalută.Ia la mama!Stiu,usor nu ti o fi nici tie....”Raspuns:Trasaturile ingrijitoarei sunt: Iubitoare de animale,buna la suflet,adica ea este foarte atenta,impresionata de puiul de urs si de animale.

c.Mara:”Of,mama o considera si acum tot o fetita,desi a terminat facultatea in vara asta.”Raspuns:Trasaturile Marei sunt:Neintelegatoare,incapatanata,adica nu asculta de mama ei,crede ca dansa o considera tot o fetita,si fata nu este de fapt asa(ti am dat un exemplu.)

Explanation:

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Water flows through a pipe of 100 mm at the rate of 0.9 m3 per minute at section A. It tapers to 50mm diameter at B, A being 1.5
pochemuha

Answer:

The velocities in points A and B are 1.9 and 7.63 m/s respectively. The Pressure at point B is 28 Kpa.

Explanation:

Assuming the fluid to be incompressible we can apply for the continuity equation for fluids:

Aa.Va=Ab.Vb=Q

Where A, V and Q are the areas, velocities and volume rate respectively. For section A and B the areas are:

Aa=\frac{pi.Da^2}{4}= \frac{\pi.(0.1m)^2}{4}=7.85*10^{-3}\ m^3

Ab=\frac{pi.Db^2}{4}= \frac{\pi.(0.05m)^2}{4}=1.95*10^{-3}\ m^3

Using the volume rate:

Va=\frac{Q}{Aa}=\frac{0.9m^3}{7.85*10^{-3}\ m^3} = 1.9\ m/s

Vb = \frac{Q}{Ab}= \frac{0.9m^3}{1.96*10^{-3}\ m^3} = 7.63\ m/s

Assuming no losses, the energy equation for fluids can be written as:

Pa+\frac{1}{2}pa.Va^2+pa.g.za=Pb+\frac{1}{2}pb.Vb^2+pb.g.zb

Here P, V, p, z and g represent the pressure, velocities, height and gravity acceleration. Considering the zero height level at point A and solving for Pb:

Pb=Pa+\frac{1}{2}pa(Va^2-Vb^2)-pa.g.za

Knowing the manometric pressure in point A of 70kPa, the height at point B of 1.5 meters, the density of water of 1000 kg/m^3 and the velocities calculated, the pressure at B results:

Pb = 70000Pa+ \frac{1}{2}*1000\ \frac{kg}{m^3}*((1.9m/s)^2 - (7.63m/s)^2) - 1000\frac{kg}{m^3}*9,81\frac{m}{s^2}*1.5m

Pb = 70000\ Pa-27303\ Pa - 14715\ Pa

Pb = 27,996\ Pa = 28\ kPa

6 0
3 years ago
Lois is in high school and enjoys studying math and science subjects. She aspires to get into the robotics industry after comple
Inessa [10]

Answer:

d.partivipate in a robotic club

hope helps

mark me please

4 0
3 years ago
A pump delivers water at 20°C between a reservoir and a water tank 24 m higher. The suction side consists of a strainer (ks = 2.
aleksandrvk [35]

Answer:

-10.83m

Explanation:

Please see the attachment

8 0
4 years ago
How can goal setting help with academic performance?
Zina [86]

Answer:

B.)It is an effective study skill.

Explanation:

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Sed is a multipurpose tool that combines the work of several filters. sed performs noninteractive operations on a data stream. s
timama [110]

Answer:

The answer is True.

Explanation:

SED is a command in UNIX for stream editors that parses and transforms text, using a simple, compact programming language. So the answer is TRUE that sed is a multipurpose tool that combines the work of several filters and performs noninteractive operations on a data stream. sed has a host of features that allow you ti select lines and run instructions on them.

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