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3 years ago

11 Notează, în caiet, trăsăturile personajelor ce se pot

1 answer:

6 0

Answer:a.Bianca:”Puiul de Urs loveste cu labele din fata in roata de cauciuc atarntata de-o sfoara”:Raspuns:Trasaturile puiului de urs sunt:jucaus,curios,interesat

b.Ingrijitoarea:”Doar un copil,asta esti matalută.Ia la mama!Stiu,usor nu ti o fi nici tie....”Raspuns:Trasaturile ingrijitoarei sunt: Iubitoare de animale,buna la suflet,adica ea este foarte atenta,impresionata de puiul de urs si de animale.

c.Mara:”Of,mama o considera si acum tot o fetita,desi a terminat facultatea in vara asta.”Raspuns:Trasaturile Marei sunt:Neintelegatoare,incapatanata,adica nu asculta de mama ei,crede ca dansa o considera tot o fetita,si fata nu este de fapt asa(ti am dat un exemplu.)

Explanation:

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As described in "A Note About Bacterial Reproduction -- and the "Culture Bias,"" the organism Epulopisciumdoes not divide by bin

zloy xaker [14]

Answer:

Explanation:

The best method that will yield significantly more accurate result is to use spectrophotometer to read the turbidity of the sample and increase in turbidity is associated with increase biomass.

5 0

3 years ago

To provide some perspective on the dimensions of atomic defects, consider a metal specimen that has a dislocation density of 105

GenaCL600 [577]

Answer:

$62.14\ \text{miles}$

$6213727.37\ \text{miles}$

Explanation:

The distance of the chain would be the product of the dislocation density and the volume of the metal.

Dislocation density = $10^5\ \text{mm}^{-2}$

Volume of the metal = $1000\ \text{mm}^3$

$10^5\times 1000=10^8\ \text{mm}\\ =10^5\ \text{m}$

$1\ \text{mile}=1609.34\ \text{m}$

$\dfrac{10^5}{1609.34}=62.14\ \text{miles}$

The chain would extend $62.14\ \text{miles}$

Dislocation density = $10^{10}\ \text{mm}^{-2}$

Volume of the metal = $1000\ \text{mm}^3$

$10^{10}\times 1000=10^{13}\ \text{mm}\\ =10^{10}\ \text{m}$

$\dfrac{10^{10}}{1609.34}=6213727.37\ \text{miles}$

The chain would extend $6213727.37\ \text{miles}$

3 0

3 years ago

Only put coolant into your radiator when the engine is _____.

Arada [10]

Only put ciilant into ur radiator when the engine is cool (D)

5 0

3 years ago

2. Why are some constraints automatically applied by the software, but you must manually apply others?

hoa [83]

Answer:

It is because constraints applied automatic by the software (CAD) are supposed to control relationships and geometry between lines, arcs and circles while those manually added are supposed to control the geometry to behave in the manner the user likes the sketch to appear when drawing.

Explanation:

CAD software enables creating sketches using the program by automatic allowing geometric constraints to perform the tasks.Geometry in lines, circles, and other geometric features show collaborating relation that facilitate sketching in the program.For example, two end points appear to make lines remain perpendicular.Other geometric constraints are parallel, and equal.However, the user can manually apply geometric constraints to a sketch to force the geometry in a manner that is suitable to the sketch drawn.That is why a user must manually apply others.

7 0

3 years ago

X cotx expansion using maclaurins theorem.

Lemur [1.5K]

It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.

<h3>What is Maclaurin Expansion?</h3>

The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

<h3>What is the explanation for the above?</h3>

as indicated above, the Maclaurin infinite series expansion is given as:

F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

If F(0) = Cot 0

F(0) = ∝ = 1/0

This is not definitive,

Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.

Learn more about Maclaurin Expansion at;
brainly.com/question/7846182
#SPJ1

4 0

2 years ago