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Alinara [238K]
3 years ago
13

11 Notează, în caiet, trăsăturile personajelor ce se pot

Engineering
1 answer:
almond37 [142]3 years ago
6 0

Answer:a.Bianca:”Puiul de Urs loveste cu labele din fata in roata de cauciuc atarntata de-o sfoara”:Raspuns:Trasaturile puiului de urs sunt:jucaus,curios,interesat

b.Ingrijitoarea:”Doar un copil,asta esti matalută.Ia la mama!Stiu,usor nu ti o fi nici tie....”Raspuns:Trasaturile ingrijitoarei sunt: Iubitoare de animale,buna la suflet,adica ea este foarte atenta,impresionata de puiul de urs si de animale.

c.Mara:”Of,mama o considera si acum tot o fetita,desi a terminat facultatea in vara asta.”Raspuns:Trasaturile Marei sunt:Neintelegatoare,incapatanata,adica nu asculta de mama ei,crede ca dansa o considera tot o fetita,si fata nu este de fapt asa(ti am dat un exemplu.)

Explanation:

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In order to fill a tank of 1000 liter volume to a pressure of 10 atm at 298K, an 11.5Kg of the gas is required. How many moles o
lesya [120]

Answer:

The molecular weight will be "28.12 g/mol".

Explanation:

The given values are:

Pressure,

P = 10 atm

  = 10\times 101325 \ Pa

  = 1013250 \ Pa

Temperature,

T = 298 K

Mass,

m = 11.5 Kg

Volume,

V = 1000 r

   = 1 \ m^3

R = 8.3145 J/mol K

Now,

By using the ideal gas law, we get

⇒ PV=nRT

o,

⇒ n=\frac{PV}{RT}

By substituting the values, we get

       =\frac{1013250\times 1}{8.3145\times 298}

       =408.94 \ moles

As we know,

⇒ Moles(n)=\frac{Mass(m)}{Molecular \ weight(MW)}

or,

⇒        MW=\frac{m}{n}

                   =\frac{11.5}{408.94}

                   =0.02812 \ Kg/mol

                   =28.12 \ g/mol

3 0
2 years ago
If the head loss in a 30 m of length of a 75-mm-diameter pipe is 7.6 m for a given flow rate of water, what is the total drag fo
Stolb23 [73]

Answer:

526.5 KN

Explanation:

The total head loss in a pipe is a sum of pressure head, kinetic energy head and potential energy head.

But the pipe is assumed to be horizontal and the velocity through the pipe is constant, Hence the head loss is just pressure head.

h = (P₁/ρg) - (P₂/ρg) = (P₁ - P₂)/ρg

where ρ = density of the fluid and g = acceleration due to gravity

h = ΔP/ρg

ΔP = ρgh = 1000 × 9.8 × 7.6 = 74480 Pa

Drag force over the length of the pipe = Dynamic pressure drop over the length of the pipe × Area of the pipe that the fluid is in contact with

Dynamic pressure drop over the length of the pipe = ΔP = 74480 Pa

Area of the pipe that the fluid is in contact with = 2πrL = 2π × (0.075/2) × 30 = 7.069 m²

Drag Force = 74480 × 7.069 = 526468.1 N = 526.5 KN

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3 years ago
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bagirrra123 [75]

Answer: um wuh anyways thxs for the points!

Explanation: ....:/

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klemol [59]

Answer:

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vitfil [10]

Answer:

Carpenter — A carpenter is someone who works with wood. They build houses and make cabinets etc.

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