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GaryK [48]
3 years ago
5

When you go on a hunting trip, you should leave a hunting plan with someone you trust. What information should the plan include?

Physics
2 answers:
cestrela7 [59]3 years ago
6 0

Answer:

Explanation:

The plan should include the information like where are you going for hunt, with whom you are going, when you will return. Plan should contain the specific directions and route you are going to take, so that in case of any miss-happening your family, friend or whom you trust will be able to track you.

Plan also need to contain the information of vehicle you are going to use during the trip.

bulgar [2K]3 years ago
4 0
You should put when you will leave, where you will be, and what time you will get back. 
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Their Period number is common means their "Principal Quantum Numbers" are same

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Part 1: Use complete sentences to explain why solar winds occur. Part 2: Give two examples in which solar winds impact Earth.
Troyanec [42]

Part 1

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Part 2

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4 0
3 years ago
A bowling ball is launched from the top of a building at an angle of 35° above the horizontal with an initial speed of 15 m/s. T
Mamont248 [21]

Let y_0 be the height of the building and thus the initial height of the ball. The ball's altitude at time t is given by

y=y_0+\left(15\dfrac{\rm m}{\rm s}\right)\sin35^\circ\,t-\dfrac g2t^2

where g=9.80\frac{\rm m}{\mathrm s^2} is the acceleration due to gravity.

The ball reaches the ground when y=0 after t=2.9\,\mathrm s. Solve for y_0:

0=y_0+\left(15\dfrac{\rm m}{\rm s}\right)\sin35^\circ(2.9\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(2.9\,\mathrm s)^2

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so the building is about 16 m tall (keeping track of significant digits).

3 0
3 years ago
Based on the principles of convection, conduction and thermal radiation, which scenario below is most similar to the following s
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3 0
3 years ago
Read 2 more answers
A 1200.0-kg car is traveling at 19m/s. The driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic f
Alja [10]
<h2>Answer</h2>

option D)

2.4 seconds

<h2>Explanation</h2>

Given in the question,

mass of car = 1200kg

speed of car = 19m/s

Force due to direction of travel

F = ma

  = 12000(a)

Force to due frictional force in reverse direction

-F = mg(friction coefficient)

   = -12000(9.81)(0.8)

<h2>-mg(friction coefficient) = ma  </h2>

(cancelling mass from both side of equation)

g(0.8) = a

(9.81)(0.8) = a

a = 7.848 m/s²

<h2>Use Newton Law of motion</h2><h3>vf - vo = a • t</h3>

where vf = final velocity

          vo = initial velocity

          a = acceleration

           t = time

0 - 19 = 7.8(t)

t = 19/7.8

  = 2.436 s

  ≈ 2.4s

5 0
3 years ago
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