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Gala2k [10]
2 years ago
9

Can anyone heelp me plzz plzz

Physics
1 answer:
Natali5045456 [20]2 years ago
4 0
I think the answer is c) 1
Hope it helps and have a good day
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2 When a cube of hot metal is placed in a beaker of cold water, the temperature of the water -
jek_recluse [69]
The answer to this is B
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3 years ago
On the Moon the acceleration due to gravity is about one sixth that on Earth. If a golfer on the Moon imparted the same initial
swat32

Explanation:

We know that that the range of the ball on the earth

R_{earth}=\frac{v_o^2sin2\theta}{g_{earth}}

therefore, range of the ball on moon

R_{moon}=\frac{v_o^2sin2\theta}{g_{moon}}

R_{moon}=\frac{v_o^2sin2\theta}{g_{earth}/12}

therefore,

R_{moon}=6R_{earth}

Therefore, the range of ball will be 6 times on the moon than that on earth

6 0
2 years ago
If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.503 X 104 T) at a distance of 15
dem82 [27]

Answer:

37.725 A

Explanation:

B = magnitude of the magnetic field produced by the electric wire = 0.503 x 10⁻⁴ T

r = distance from the wire where the magnetic field is noted = 15 cm = 0.15 m

i = magnitude of current flowing through the wire = ?

Magnetic field by a long wire is given as

B = \frac{\mu _{o}}{4\pi }\frac{2i}{r}

Inserting the values

0.503\times 10^{-4} = (10^{-7})\frac{2i}{0.15}

i = 37.725 A

6 0
3 years ago
State four components of a circuit
makvit [3.9K]

Answer:

» Battery or cell

» Switch

» Connecting wires

» Resistor or appliance

7 0
3 years ago
A small bolt with a mass of 41.0 g sits on top of a piston. The piston is undergoing simple harmonic motion in the vertical dire
EleoNora [17]

Answer:

Amplitude will be equal to 0.091 m

Explanation:

Given mass of the slits = 41 gram = 0.041 kg

Frequency f = 1.65 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 1.65=10.362rad/sec

Angular frequency is equal to \omega =\sqrt{\frac{k}{m}}

10.362 =\sqrt{\frac{k}{0.041}}

Squaring both side

107.371 ={\frac{k}{0.041}}

k = 4.40 N/m

For vertical osculation

mg=kA

0.041\times 9.8=4.40\times A

A = 0.091 m

So amplitude will be equal to 0.0391 m

8 0
3 years ago
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