Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, and is the primary interaction occurring in ionic compounds.A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.
Answer:
![Potential\ Energy=Work \ Done=2.301*10^{-18} J](https://tex.z-dn.net/?f=Potential%5C%20Energy%3DWork%20%5C%20Done%3D2.301%2A10%5E%7B-18%7D%20J)
Work done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is ![2.301*10^{-18} Joules](https://tex.z-dn.net/?f=2.301%2A10%5E%7B-18%7D%20Joules)
Explanation:
The potential energy is given by:
U=Q*V
where:
Q is the charge
V is the potential difference
Potential Difference=V=![\frac{kq}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bkq%7D%7Br%7D)
So,
![Potential\ Energy=\frac{Qkq}{r} \\Q=q\\Potential\ Energy=\frac{kq^2}{r}](https://tex.z-dn.net/?f=Potential%5C%20Energy%3D%5Cfrac%7BQkq%7D%7Br%7D%20%5C%5CQ%3Dq%5C%5CPotential%5C%20Energy%3D%5Cfrac%7Bkq%5E2%7D%7Br%7D)
Where:
k is Coulomb Constant=![8.99*10^9 Nm^2/C^2](https://tex.z-dn.net/?f=8.99%2A10%5E9%20Nm%5E2%2FC%5E2)
q is the charge on electron=![-1.6*10^-19 C](https://tex.z-dn.net/?f=-1.6%2A10%5E-19%20C)
r is the distance=![3.0*10^{-10}m](https://tex.z-dn.net/?f=3.0%2A10%5E%7B-10%7Dm)
For 3 Electrons Potential Energy or work Done is:
![Potential\ Energy=3*\frac{kq^2}{r}](https://tex.z-dn.net/?f=Potential%5C%20Energy%3D3%2A%5Cfrac%7Bkq%5E2%7D%7Br%7D)
![Potential\ Energy=3*\frac{(8.99*10^9)(-1.6*10^{-19})^2}{3*10^{-10}}\\Potential\ Energy=2.301*10^{-18} J](https://tex.z-dn.net/?f=Potential%5C%20Energy%3D3%2A%5Cfrac%7B%288.99%2A10%5E9%29%28-1.6%2A10%5E%7B-19%7D%29%5E2%7D%7B3%2A10%5E%7B-10%7D%7D%5C%5CPotential%5C%20Energy%3D2.301%2A10%5E%7B-18%7D%20J)
Work done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is ![2.301*10^{-18} Joules](https://tex.z-dn.net/?f=2.301%2A10%5E%7B-18%7D%20Joules)
Answer:
Explanation:
Applied force, F = 18 N
Coefficient of static friction, μs = 0.4
Coefficient of kinetic friction, μs = 0.3
θ = 27°
Let N be the normal reaction of the wall acting on the block and m be the mass of block.
Resolve the components of force F.
As the block is in the horizontal equilibrium, so
F Cos 27° = N
N = 18 Cos 27° = 16.04 N
As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .
The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N .... (1)
The vertically downward force acting on the block is mg - F Sin 27°
= mg - 18 Sin 27° = mg - 8.172 ... (2)
Now by equating the forces from equation (1) and (2), we get
mg - 8.172 = 6.42
mg = 14.592
m x 9.8 = 14.592
m = 1.49 kg
Thus, the mass of block is 1.5 kg.
Potential energy because it has enough energy to do work but non has been done yet.