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Hitman42 [59]
3 years ago
9

Miguel is skipping rocks across the surface of a lake. After he throws it, each stone goes through the following motions: the st

one moves toward the water the stone hits the surface of the water and bounces off gravity pulls the stone back toward the water the stone enters the water and slows down In which part of the stone's movement is the stone most like a beam of light that is being refracted?
Physics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

the stone enters the water and slows down

Explanation:

Solution:

- When light is refracted it speed is slowed down or increases depending on the medium it enters. This depends on the ratio of air-water refractive index ratio.

- The speed of an object in air is faster than speed of an object in water. Because the refractive index of air is less than that of water. In refraction, the light changes direction slightly because it slows down or speeds up, depending on what medium it is changing into.

- From this we could say as the rock enters the water and slows down it models as if the light has been refracted.

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an airplane is traveling at an altitude of 31,360. a box of supplies is driped from the cargo hold how long will it take to reac
VMariaS [17]

Answer: 1,600 seconds

Explanation:

31,360/9.8 = 3,200.

Then divide 3,200/2 = 1,600

7 0
3 years ago
Two piano strings produce beats. Frequencies of the strings are 1560 Hz. and 1563 Hz. Choose the correct frequency of the beats.
kakasveta [241]

Beat frequency is given by the difference of two frequencies played together

f_{beat} = |f_1 - f_2|

given that

f_1 = 1560 Hz

f_2 = 1563 Hz

Now

f_{beat} = |1560- 1563| Hz

f_{beat} = 3 Hz

3 0
3 years ago
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Lyrx [107]
You need to finish the question
6 0
2 years ago
A 4.2-m-diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad????s. Its total moment of inertia is 136
Lina20 [59]

Answer:

A) 0.44 rad/s

B) 3.091 rad/s

Explanation:

Initial angular momentum must be equal to final angular momentum.

W1 = 0.80 rad/s

I = 1360 kgm^2

Initial moment Iw = 0.8 x 1360 = 1088 rad-kg-m^2/s

For second case

I = (65 x 4)4.2 + 1360 = 2452 kg-m2-rad/s

New momentum = 2452 x W2

Where w2 = final angular momentum

= 2452W2

Equating both moment,

1088 = 2452W2

W2 = 0.44 rad/s0

If they were on it before,

Initial momentum

I = 1360 - (60 x 4)4.2

= 352 rad-kg-m^2/s

352W1 = 1088

W1 = 3.091 rad/s

5 0
3 years ago
5. You are skateboarding on top of a small hill and take a break. You have 100 J of potential energy. If
Sholpan [36]

Given the potential energy of 100 J, the height of the hill is 0.128 m (12.8 cm)

Explanation:

The gravitational potential energy of an object is given by:

U=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

In this problem, we have

U = 100 J is the potential energy of the person

g=9.8 m/s^2 is the acceleration of gravity

m = 80 kg is the mass of the person

Solving for h, we find at what height the person is:

h=\frac{U}{mg}=\frac{100}{(80)(9.8)}=0.128 m = 12.8 cm

Learn more about gravitational potential energy here:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

5 0
2 years ago
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