Ask question

Ask question

All categories

3 years ago

15

___________ is the process by which wind removes surface materials.

2 answers:

Travka [436]3 years ago

4 0

The answer is deflation...have a good day

kherson [118]3 years ago

4 0

<h3><u>Answer;</u></h3>

Deflation

<u>Deflation</u> is the process by which wind removes surface materials.

<h3><u>Explanation</u>;</h3>

Erosion refers to a process in which soil, rock, and other surface material are removed from their location and transported to another by natural agents such as water and wind.
<em><u>The main mechanism of wind erosion is deflation. Deflation involves erosion by wind of loose material from flat areas of dry uncemented sediments such as those in deserts, dry lake beds, flood plains etc. The removed particles are then transported to another region where they may form sand dunes on a beach or in a desert.</u></em>

You might be interested in

Elaborate on the suitability of "cola" type drinks to polish chrome surfaces.

nexus9112 [7]

The answer is t<span>he phosphoric acid in cola easily removes dirt and grime. The </span>"cola" type drinks is suitable to polish chrome surfaces. Cola contains a very diluted solution of phosphoric acid, which can remove rust, dirt, and grime from chrome surface.

3 0

4 years ago

Ask Your Teacher The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s

adell [148]

Answer:

$\theta = 20\ rev$

Explanation:

Case 1

Given,

initial angular speed = 0 rev/s

final angular speed = 2 rev/s

time, t = 7 s

angular acceleration of the washer

$\alpha = \dfrac{\omega_f-\omega_i}{t}$

$\alpha = \dfrac{2-0}{7}$

$\alpha = 0.286\ rev/s^2$

using equation of rotational motion

$\omega_f^2 = \omega_i^2 + 2 \alpha \theta_1$

$2^2 = 0^2 + 2\times 0.286 \times \theta_1$

$\theta_1 = 7 rev$

Case 2

Given,

initial angular speed = 2 rev/s

final angular speed = 0 rev/s

time, t = 12 s

angular acceleration of the washer

$\alpha = \dfrac{\omega_f-\omega_i}{t}$

$\alpha = \dfrac{0-2}{13}$

$\alpha = -0.154\ rev/s^2$

using equation of rotational motion

$\omega_f^2 = \omega_i^2 + 2 \alpha \theta_2$

$0^2 = 2^2 + 2\times (-0.154) \times \theta_2$

$\theta_2 = 13 rev$

total revolution in this case

$\theta = \theta_1 + \theta_2$

$\theta =7 +13$

$\theta = 20\ rev$

total revolution of the washer is equal to 20 rev.

6 0

3 years ago

One strategy in a snowball fight is to throw

Oxana [17]

second question: How many seconds after the first snowball

should you throw the second so that they

arrive on target at the same time?

Answer in units of s.

Answer:

Part 1: 28°

Part 2: 1.367

Explanation:

Part 1:

Given: 62°

Simple

θ = 90°- 62°

<u>θ = 28°</u>

Part 2:

Y-direction

Δy $=v_{yo} t+\frac{1}{2} a_{y} t^{2}$

$0=[16.2sin(62)]t_{1}+1/2(-9.8)t_{1}^{2} \\$

$t_{1} =\frac{2[16.2sin(62)]}{9.8}$

$t_{1}=2.91913s$

$0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}$

$t_{2} =\frac{2[16.2sin(28)]}{9.8}$

$t_{2}=1.55213s$

Δt $=t_{1}-t_{2}$

Δt $=2.91913-1.55213$

<u>Δt= 1.367s</u>

Hope it helps :)

7 0

3 years ago

I feel dvmb for asking this question but... help? Please?

VMariaS [17]

<u>Force</u>, it can speed up or slow down an object which can change the direction in which an object is moving.

8 0

3 years ago

In order to decrease the required centripetal acceleration for a car driving around a turn, the driver could

musickatia [10]

Answer:

Release the pressure on the gas peddle

Explanation:

If you turn around to fast you cant make a tighter turn around but if its slow you can turn around tighter.

4 0

3 years ago