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Natalka [10]
3 years ago
15

Write the balanced chemical equation for the combination (synthesis) reaction of magnesium with oxygen gas. phases are optional.

Chemistry
1 answer:
NISA [10]3 years ago
6 0
The answer to this question would be:2 Mg<span> + O</span>2<span> = 2 MgO

Magnesium is a metal that can be oxidized easily. The reaction of magnesium and oxygen can be said as burning the magnesium. The reaction can provide a bright light with violet color. Magnesium used mostly in solid state and the oxygen is gas.</span>
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Detecta cuál de las siguientes fórmulas estructurales no cumple con la tetravalencia del carbono (formar cuatro enlaces)
o-na [289]

El ejercicio completo con las formulas es el siguiente:

cuál de las siguientes fórmulas no cumple con la tetravalencia del átomo de carbono.

a. CH3-CH2-CH2-OH

b. CH3-CH=CH2

c. CH3-CH2=CH2

d. CH3-CH2-CH3

Answer:

La respuesta correcta es la opción C

Explanation:

En la formula C, podemos ver claramente que no se cumple con la tetravalencia del carbono pues al sumar el total de las valencias del carbono nos da 5

CH3 - CH2  =   CH2 = Total de valencias del carbono 5

         1 + 2+  2   =  5

Para que la formula sea correcta debe eliminarse un hidrogeno quedando la formula de la siguiente manera:

                      CH3   -  CH   =   CH2

                                 1 +  1  + 2 =  4

8 0
3 years ago
Which particle has no mass and no charge?<br> O alpha<br> O beta<br> gamma<br> O<br> neutron
Olegator [25]

Answer:

Neutrons

Explanation:

6 0
3 years ago
The job the part does within organism is the
kramer
The answer it the function
7 0
3 years ago
Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr
pantera1 [17]

Answer:

m_{CuO}=93.6gCuO

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO

Regards.

6 0
3 years ago
The balance of the following equations
myrzilka [38]
A. 6 NaOH   +  2(NH4)3 PO4  ----->  2Na PO4  +  6H2O  +   6NH3

b. C2 H6 O  + 3O2  ---->   2CO2  +  3H2O
5 0
3 years ago
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