The answer Is (1)...Straight Isomer when you put them together.
Hope that helps!!!
The answer is the 3rd one down I think
<u>Answer:</u> The temperature to which the gas in the syringe must be heated is 720.5 K
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=1.88atm\\V_1=285mL\\T_1=355K\\P_2=2.50atm\\V_2=435mL\\T_2=?K](https://tex.z-dn.net/?f=P_1%3D1.88atm%5C%5CV_1%3D285mL%5C%5CT_1%3D355K%5C%5CP_2%3D2.50atm%5C%5CV_2%3D435mL%5C%5CT_2%3D%3FK)
Putting values in above equation, we get:
![\frac{1.88atm\times 285mL}{355K}=\frac{2.50atm\times 435mL}{T_2}\\\\T_2=\frac{2.50\times 435\times 355}{1.88\times 285}=720.5K](https://tex.z-dn.net/?f=%5Cfrac%7B1.88atm%5Ctimes%20285mL%7D%7B355K%7D%3D%5Cfrac%7B2.50atm%5Ctimes%20435mL%7D%7BT_2%7D%5C%5C%5C%5CT_2%3D%5Cfrac%7B2.50%5Ctimes%20435%5Ctimes%20355%7D%7B1.88%5Ctimes%20285%7D%3D720.5K)
Hence, the temperature to which the gas in the syringe must be heated is 720.5 K