Answer:
223.08 K
Explanation:
First we <u>convert 173.0 °C to K</u>:
- 173.0 °C + 273.16 = 446.16 K
With the absolute temperature we can use <em>Charles' law</em> to solve this problem:
Where in this case:
We <u>input the data</u>:
- 446.16 K * 50 L = T₂ * 100 L
And <u>solve for T₂</u>:
The unknown of this problem is the experimental percent of water in the compound in order to remove the water of hydrogen, given the following:
Mass of crucible, cover and contents before heating 23.54 g
Mass of empty crucible and cover 18.82 g
Mass of crucible, cover, and contents after heating to constant mass 20.94 g
In order to get the answer, determine the following:
Mass of hydrated salt used = 23.54 g – 18.82 g = 4.72 g
Mass of dehydrated salt after heating = 20.94 g – 18.82 g = 2.12 g
Mass of water liberated from salt = 4.72 g – 2.12 g = 2.60 g
Then solve the percent of water in the hydrated salt by:
% water = (mass of water / mass of hydrated salt) x 100
% water = 2.60 g / 4.72 g x 100
% water = 55.08 % in the compound
Answer:
have luster i think i dont know
Explanation:i need points
Answer:
all atoms of a given element have the same number of protons but may have different masses
Explanation:
After the discovery of isotopes, scientists were able to conclude that all atoms of a given element have the same number of protons but may have different masses.
Isotopes are atoms of an element that have the same atomic number but different mass number.
The atomic number is the number of protons within an atom.
Mass number is the number of protons and number of neutrons.
Therefore, all atoms of a given element have the same number of protons but different mass.
Reaction on positive electrode (cathode):
PbSO₄₍s₎ + 2H₂O₍l₎ → 2e⁻ + PbO₂₍s₎ + 4H⁺₍aq₎ + SO₄²⁻₍aq₎.
s - solid.
l - liquid.
aq - dissolve in water.
PbSO4 is converted to Pb at one electrode (anode) and to PbO₂ at the other (cathode). Lead battery can be recharged, during recharging, an external source of energy is used.