Answer: In the equations that you have given, we have a dependent system.
2x + y = 8 (I assumed that you meant to type y instead of 7)
6x + 3y = 24
To use Cramer's Rule, we have to take the determinant of 3 different matrices written in the problem. Taking the determinant of the coefficient matrix produces a zero.
2 1 This is the coefficient matrix.
6 3
6 - 6 = 0
Since this is 0, the rest of the work will be undefined meaning the systems are dependent (or they are the versions of the same equation).
Answer:
x=2
Step-by-step explanation:
logx (2x)^3 = 6
We can rewrite without the exponent
3 logx (2x) = 6
Divide by 3
3/3 logx (2x) = 6/3
logx (2x) = 2
Raise each side to the base x
x^ logx (2x) =x^ 2
2x = x^2
Subtract 2x from each side
2x-2x = x^2 -2x
0 = x^2 -2x
Factor an x
0 = x(x-2)
Using the zero product property
x =0 x-2 =0
x =0 x=2
We cannot have a base of 0, so x cannot equal 0
x=2
Answer: Commutative property of multiplication
Step-by-step explanation: The problem 6 · 1 = 1 · 6 demonstrates the commutative property of multiplication.
In other words, the commutative property of multiplication says that changing the order of the factors does not change the product.
So for example here, 6 · 1 is equal to 6 and 1 · 6 also equals 6.
Since 6 = 6, we can easily see that 6 · 1 must be equal to 1 · 6.
In more general terms, the commutative property of multiplication can be written as a · b = b · a where <em>a</em> and <em>b</em> are variables that can represent any numbers.
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5 : 20
Divide both sides by 5 to get the answer
5/5 = 1
20/5 = 4
Thus, the answer is 1 : 4
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Answer:
The range would not change
Step-by-step explanation:
If we replaced one of the 7s with a 5, we still have a 7. The range will be the highest number minus the lowest number (7 - 1 = 6). So the range would still not change because we still have another 7.
