What is the temperature of 1.2 moles of helium gas at 2.57 ATM if it occupies 15.5L of volume

1 answer:

8 0

We will assume helium to behave as an ideal gas and apply the ideal gas law:
PV = nRT
For pressure measured in atmospheres and volume measured in liters, the value of the molar gas constant is 0.082. Therefore:
T = PV / nR
T = (2.57 x 15.5) / (1.2 x 0.082)
T = 404.8 Kelvin

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