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3 years ago

What is the temperature of 1.2 moles of helium gas at 2.57 ATM if it occupies 15.5L of volume

1 answer:

8 0

We will assume helium to behave as an ideal gas and apply the ideal gas law:
PV = nRT
For pressure measured in atmospheres and volume measured in liters, the value of the molar gas constant is 0.082. Therefore:
T = PV / nR
T = (2.57 x 15.5) / (1.2 x 0.082)
T = 404.8 Kelvin

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2 years ago

to form brass, copper and zinc combine but do not chemically bond. brass is a(n) ________. a atom b element c compound d

umka21 [38]

Answer: Mixture

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3 years ago

Brenda rode a skateboard 95 meters west. It took her 20 seconds. What was

Artemon [7]

Answer:

D. 4.75 m/s west

Explanation:

You can immediately get the answer once you know the formula for velocity.

The formula for velocity is: Velocity (V) = $\frac{distance (d)}{time (t)}$

The distance is 95 meters while the time is 20 seconds. All you have to do is to divide 95 meters by 20 seconds.

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V = $\frac{95 meters}{20 seconds}$

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3 years ago

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3 years ago

How many moles of k3po4 can be formed when 4.4 moles of h3po4 react with 3.8 moles of koh? h3po4 + koh yields h2o + k3po4 be sur

schepotkina [342]

the balanced chemical equation for the reaction is as follows

H₃PO₄ + 3KOH ---> K₃PO₄ + 3H₂O

stoichiometry of H₃PO₄ to KOH is 1:3

first we have to find which the limiiting reactant is

as the amount of product formed depends on the amount of limiting reactant present

number of H₃PO₄ moles reacted - 4.4 mol

if H₃PO₄ is the limiting reactant

1 mol of H₃PO₄ reacts with 3 mol of KOH

then 4.4 mol of H₃PO₄ reacts with - 3 x 4.4 mol = 13.2 mol of KOH

but only 3.8 mol of KOH is present

therefore KOH is the limiting reactant

stoichiometry of KOH to K₃PO₄ is 3:1

number of KOH moles reacted - 3.8 mol

therefore number of K₃PO₄ formed = number of KOH moles reacted / 3

= 3.8 mol / 3 = 1.3 mol

answer is 1.3 mol of K₃PO₄

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3 years ago