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Answer 1) : According to the complete question attached in the answer,
The radial wave function which is denoted by shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.
Also, the radial probability distribution curve denoted as shown in blue color is observed to touch zero, and shows the place of radial node.
Therefore, the total number of nodes will include both the kinds which has radial and angular nodes which will be represented by <em>'n'</em>.
It is observed that for any atomic orbital, the total number of nodes will be n-1 .
Considering the s orbital of the hydrogen, which has zero angular momentum (l); (l=0), as it has zero angular nodes.
Hence, there will be only radial nodes, which is
(n−1 = total number of radial nodes in s orbitals)
According to the image, there are 4 radial nodes shown, so n = 5 (as n-1 = 4; therefore, n = 5)
This represents the 5s orbital.
Answer 2) The radial nodes are observed in I'm seeing radial nodes at
,
,
and
.
where represents the hydorgen bohr atomic radius = 0.0529177 nm
Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.
Answer:
Explanation:
When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.
The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.
The number to be dropped (3) is less than 5, so you drop it.