There are two uncharged objects, A and B. Some electrons move from A to B. How does the charge of the two objects change?

1 answer:

5 0

A becomes positive, while b is now negative. Basically, electrons are negative particles. If they go to somewhere, they make the somewhere they go to negative.

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If a system requires 150 j of input work and produces 123 J of output work, whats its effiency

Yuki888 [10]

The effiency of a machine is

(output work or energy) / (input work or energy) .

For the system described in the question, that's

(123 J) / (150 J) = 0.82 = 82% .

4 0

3 years ago

A hammer taps on the end of a 5.0-mm-long metal bar at room temperature. A microphone at the other end of the bar picks up two p

katrin2010 [14]

Answer:

810.37 m/s

Explanation:

s = Displacement = 5 m

$v_a$ = Speed of sound in air = 343 m/s

Time taken to travel the distance

$t'=\dfrac{s}{v_a}\\\Rightarrow t'=\dfrac{5}{343}\\\Rightarrow t'=0.01457\ s$

Time for the sound in metal

$t=0.01457-8.4\times 10^{-3}=0.00617\ s$

Speed of sound is given by

$v=\dfrac{s}{t}\\\Rightarrow v=\dfrac{5}{0.00617}\\\Rightarrow v=810.37277\ m/s$

The speed of sound in the metal is 810.37 m/s

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3 years ago

The hydraulic lift in a car repair shop has an output diameter of 30 cm and is to lift cars up to 2000 kg. determine the fluid g

leonid [27]

Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2

Thank you for posting your question here at brainly. I hope the answer helps. </span>

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3 years ago

Read 2 more answers

A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is

ella [17]

Answer:

1.97 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0$

Solving the above equation we get

$t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89$