Answer:
Option C. 70 Ω
Explanation:
Data obtained from the question include:
Resistor (R) = 20 Ω
From diagram given ABOVE, we observed the following
1. R and R are in parallel connections.
2. 2R and 2R are in parallel connections.
3. 4R and 4R are in parallel connections.
Next, we shall determine the equivalent resistance in each case.
This is illustrated below:
1. Determination of the equivalent resistance for R and R parallel connections.
R = 20 Ω
Equivalent R = (R×R) /(R+R)
Equivalent R = (20 × 20) /(20 + 20)
Equivalent R = 400/40
Equivalent R = 10 Ω
2. Determination of the equivalent resistance for 2R and 2R parallel connections.
R = 20 Ω
2R = 2 × 20 = 40 Ω
Equivalent 2R = (2R×2R) /(2R+2R)
Equivalent 2R = (40 × 40) /(40 + 40)
Equivalent 2R = 1600/80
Equivalent 2R = 20 Ω
3. Determination of the equivalent resistance for 4R and 4R parallel connections.
R = 20 Ω
4R = 4 × 20 = 80 Ω
Equivalent 4R = (4R×4R) /(4R+4R)
Equivalent 4R = (80 × 80) /(80 + 80)
Equivalent 4R = 6400/160
Equivalent 4R = 40 Ω
Thus, the equivalence of R, 2R and 4R are now in series connections. We can obtain the equivalent resistance in the circuit as follow:
Equivalent of R = 10 Ω
Equivalent of 2R = 20 Ω
Equivalent of 4R = 40 Ω
Equivalent =?
Equivalent = Equivalent of (R + 2R + 4R)
Equivalent = 10 + 20 + 40
Equivalent = 70 Ω
Therefore, the equivalent resistance between point A and B is 70 Ω.
